Answer:
5/2
Step-by-step explanation:
Answer:
Step-by-step explanation:
So add the numbers on each side together
Answer:
15/56
Step-by-step explanation:
5 people have a license
3 people don't
? = Probability that first person has a license and second does not
We can divide the problem into two sections, the first being the probability of the first person having a license, and the second section is the probability that the second person doesn't have a license.
P1 = Probability of the first person having a license, there are 5 out of 8 person having a license, thus P1 = 5/8.
P2 = Probability of the second person having a license. There are 3 people not having a license, out of 8-1 = 7 persons available, since one is taken already from the first choice, therefore P2 = 3/7.
P1 and P2 are dependent events, thus P(1,2) = P1 * P2.
P(1,2) = P1 * P1 = 5/8 * 3/7 = 15/56
X is the number of dog
y is the number of cats , y=40
25% of x is 25*x /100=25x/100=x/4
<span>and there are 25% more cats than dogs means y+ x/4=x implies 40=(3/4)x
</span>x=160/3=53
so the number of dogs is 53 and the number of cats is 40
the total number is 53+40=93
Since we removed one ace out of 52 cards now remains 51 cards and 3 aces.
The answer is 3/51
