Solve each equation by factoring, by taking square roots, or by grouping. When necessary round to the nearest hundredth.
1 answer:
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Answer:
- sin = 0.776595
- tan = 1.23269
- sec = 1.58730
- csc = 1.28767
- cot = 0.811234
Step-by-step explanation:
Cosine is the name of a function of an angle, not a triangle. We have drawn a triangle containing an angle (α) whose cosine is 0.63.
The cosine is the ratio of the adjacent leg of a right triangle to the hypotenuse, where "adjacent" refers to the angle of interest. In our triangle, we have ensured the cosine is 0.63 by making the adjacent leg be 63 and the hypotenuse be 100.
The length of the opposite leg can be found from the Pythagorean theorem.
opp = √(100² -63²) = √6031
The sine function is the ratio of that to the hypotenuse:
sin(α) = (√6031)/100 ≈ 0.776595
The tangent function is the ratio of opposite to adjacent sides:
tan(α) = (√6031)/63 ≈ 1.23269
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The secant is the inverse of the cosine:
sec(α) = 1/0.63 ≈ 1.58730
The cosecant is the inverse of the sine:
csc(α) = (100√6031)/6031 ≈ 1.28767
and the cotangent is the inverse of the tangen:
cot(α) = (63√6031)/6031 ≈ 0.811234
Answer:
0.2
Step-by-step explanation:
If two number cubes as tossed then the total possible out comes are
Total = {(1,1),(2,1),(3,1),(4,1),(5,1),(6,1),(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(1,3),(2,3),(3,3),(4,3),(5,3),(6,3),(1,4),(2,4),(3,4),(4,4),(5,4),(6,4),(1,5),(2,5),(3,5),(4,5),(5,5),(6,5),(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}
Number of elements in sample space are
n(S)=36
Let A and B represent the following events.
A = The sum will be 4.
A = {(1,3),(2,2),(3,1)}
n(A) = 3
B = The sum is less than or equal to 6.
B = {(1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)}
n(B)=15
Intersection of both events is
A∩B = {(1,3),(2,2),(3,1)}
n(A∩B) = 3
We need to find the probability that the sum will be 4, given that the sum is less than or equal to 6.
Therefore, the required probability is 0.2.