Ask question

Ask question

All categories

2 years ago

11

BRAINLIEST AND 25 POINTS

1 answer:

ioda2 years ago

5 0

Answer:

down 3, left 1.

reflection over y-axis

yes, the 2 figures are congruent

Step-by-step explanation:

You might be interested in

Michael has a weekly food budget of $62. If he plans to budget the same amount for each of the 7 days of the week, what is the m

garri49 [273]

Answer:

62/7

Step-by-step explanation:

8 0

2 years ago

Write the fraction as a product of a whole number and a unit fraction.<br><br> 7/8

aleksklad [387]

The unit fraction of 7/8 is 1/8

7 0

2 years ago

Pam draws three scalene triangles. In each figure, she measures each angle, as shown.

Ganezh [65]

Answer:

the answer is c.

Step-by-step explanation:

there's no explanation

7 0

2 years ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago

Add or subtract. Express in simplest form.<br> -4 1/3 +1 1/6

ratelena [41]

You would add because that is just how i thought of it

4 0

2 years ago