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artcher [175]
3 years ago
7

Determine whether the equation is linear or not. Then graph the equation by finding and plotting ordered-pair

Mathematics
1 answer:
Ghella [55]3 years ago
4 0

Answer:

it is linear the above given equation.

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Aria paid $75,000 for her house. its property value increased by 2.2% per year. when aria sold her house after eleven years, how
Wewaii [24]

Answer:

D

Step-by-step explanation:

Converting percent to decimal : 2.2/100 = 0.022

Finding 2.2$ of $75k : 75,000 x 0.022 = $1,650 (also the increase in one year)

Finding how much it was worth after 11 years :

(75,000 x 0.022) x 11 = $18,150 or 1,650 x 11 = $18,150

Now add the product to the regular amount to find out the answer:

75,000 + 18,150 = $93,150 (which is how much it increased after 11 years)

3 0
2 years ago
Expand : (3x+5y)²<br>please answer​
alukav5142 [94]

Answer:

FOIL:  9x^2 +30xy + 25y^2

(3x + 5y)(3x+5y)

F: 3x*3x

O: 3x*5y

I: 5y*3x

L: 5y*5y

9x^2 +30xy + 25y^2

Step-by-step explanation:

4 0
3 years ago
Which amount is greater, 5 feet or 2 yards?
Vedmedyk [2.9K]

Answer:

2 yards

Step-by-step explanation:

6 0
2 years ago
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Jeremy earned $33,000 after working for 44 weeks. How much money did Jeremy earn each week? Show Your Work
dmitriy555 [2]

Answer: jimmy needs a new job

Step-by-step explanation:

7 0
3 years ago
EasyElectrics supermarket orders light bulbs from suppliers, AA Electronics and AAA Electronics. EasyElectrics purchases 30% of
saw5 [17]

Answer: (a) 0.006

               (b) 0.027

Step-by-step explanation:

Given : P(AA) = 0.3 and P(AAA) = 0.70

Let event that a bulb is defective be denoted by D and not defective be D';

Conditional probabilities given are :

P(D/AA) = 0.02 and P(D/AAA) = 0.03

Thus P(D'/AA) = 1 - 0.02 = 0.98

and P(D'/AAA) = 1 - 0.03 = 0.97

(a) P(bulb from AA and defective) = P ( AA and D)

                                                       = P(AA) x P(D/AA)

                                                       = 0.3 x 0.02 = 0.006

(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)

                         = P(AA) x P(D/AA) + P(AAA) x P(D/AAA)

                         = 0.3(0.02) + 0.70(0.03)

                         = 0.027

3 0
3 years ago
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