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2 years ago

How do you write 9 7/9 as a decimal?

Mathematics

1 answer:

Sav [38]2 years ago

3 0

Answer:

9.777777778

Step-by-step explanation:

7/9 written as a decimal is 0.777777778 when we add this on to the whole number 9, we get 9.777777778.

hope this helps!

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NEED HELP ASAP!!!!!!

tino4ka555 [31]

Answer:

x=57

Step-by-step explanation:

63+60= 123

A triangle is 180 degrees

180-123= 57

x=57

5 0

2 years ago

Read 2 more answers

A cylinder has a radius of 6 inches and is 15 inches tall. what is the volume of the cylinder? express the answer in terms of pi

Vikki [24]

The volume of a cylinder that has a radius of 6 inches and is 15 inches tall is 540 π cubic inches

<h3>How to calculate the volume of a cylinder?</h3>

The formula for calculating the volume of cylinder is expressed as:

V = πr²h

where

r is the radius

h isthe height

Given the following parameters

h = 15in

r = 6in

substitute

V = 6^2 * 15π
V = 540 π cubic inches

Hence the volume of a cylinder that has a radius of 6 inches and is 15 inches tall is 540 π cubic inches

Learn more on volume of a cylinder here: brainly.com/question/9554871

6 0

1 year ago

Plssssssssssssssssssssssssssssssssssssss

solniwko [45]

Answer:

c. quadrilateral

Step-by-step explanation:

All of the sides are different lengths, so the quadrilateral cannot be a parallelogram, rhombus, or square.

Its best descriptor is parallelogram.

_____

A parallelogram has opposite sides parallel and congruent. A rhombus also has adjacent sides congruent. A square is a special case of rhombus in which the corner angles are right angles.

5 0

1 year ago

Solve the equation on the interval [0,2π]

WARRIOR [948]

$\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
\\\\\\
\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
\begin{cases}
0\\
\pi \\
2\pi 
\end{cases}\\\\
-------------------------------$

$\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0$

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

$\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
sin(x)= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}
\\\\\\
sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}
\\\\\\
sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}$

$\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
----------\\
\approx~0.252680~radians\\
\qquad or\\
\approx~14.47751~de grees\\
----------\\
\pi -0.252680\\
\approx 2.88891~radians\\
\qquad or\\
180-14.47751\\
\approx 165.52249~de grees
\end{cases}$

3 0

3 years ago

What is the slope and y-intercept for the graph of the equation Y= 4/5 x - 3 ?

vichka [17]

So,

The slope-intercept form is as follows:
y = mx + b

"m" is the slope, and "b" is the y-intercept. The y-intercept for this equation is (0,b).

Our equation is $y= \frac{4}{5} x-3$

That means that $\frac{4}{5}$ is the slope, and -3 is the y-intercept.

5 0

3 years ago