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Marina CMI [18]
2 years ago
6

Prove these identities (i) secx cosecx - cotx = tanx​

Mathematics
1 answer:
brilliants [131]2 years ago
3 0

Answer:

(A)\frac 1 {cosx} \frac 1 {sin x}  - \frac {cosx} {sin x} = \frac {sin x} {cosx} \\\\(B)\frac{1-cos^2 x }{cos x sin x} = \frac {sin x} {cosx} \\\\(C) \frac{(sin^2x + cos^2x)-cos^2 x }{cos x sin x} = \frac {sin x} {cosx} \\\\(D) \frac{sin^2x }{cos x sin x} = \frac {sin x} {cosx}\\\\(E)\frac {sin x}{cos x} = \frac {sin x}{cos x}

In step A, you replace all trigonometric functions with their definitions in terms of sine and cosine.

In step B, you add the two together as you add fractions.

In step C, you replace 1 with the sum of the squares of sine and cosine.
In step D, you add the cosine terms together so they disappear.

In step E, finally, you divide numerator and denominator by sin x.

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First, we are going to do this in slope intercept form and then change the form to standard form, which is Ax + By = C

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m = y sub2  - y sub1 divided by the change in the X coordinates  x sub2 – x sub1              

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(1, -6) the 1 is x sub 1  and the 6 is y sub 1

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so equation now is m = -1

So now again referring back to the slope intercept of the line we now know y = -1 + b.  We still have to determine b and the y intercept, and we can do this by using one of the given points and substituting in the value for y and x, and then solve for b.  Since these points are on the line, they must satisfy this equation.  If we use the first coordinates, we would substitute 1 for x and -6 for y.  

-6 =  -1 times x, which is 1 + b

b = -5

construct the line equation y = mx + b where m = -1 & b = -5

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The standard form of a linear equation is Ax + By=CA x + By = C .   Move all terms containing variables to the left side of the equation.

Add x to both sides of the equation.

y + x = -5

Reorder y & x

x + y = -5

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