2 years ago

If DE = X+1, EF = x-2, DF =15, and E is between D and F. then DE = ?

Mathematics

1 answer:

mart [117]2 years ago

8 0

Answer:

X =8

Step-by-step explanation:

DF = DE + EF

15 = X+1 + X-2

16 = 2X

X = 8

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If rhe discriminant of a quadratic equation is equal to -8 which statement describes the roots

Nastasia [14]

Answer:

Step-by-step explanation:

Given

$Discriminant = -8$

Required

Determine the type of roots

Represent Discriminant with D; such that

$D = -8$

D is calculated as thus

$D = b^2 - 4ac$

And it has the following sequence of results

When $D > 0;$ then the roots of the quadratic equation are real but not equal

When $D = 0;$ then the roots of the quadratic equation are real and equal

When $D < 0;$ then the roots of the quadratic equation are complex or imaginary

Given that $D = -8$ ; This means that $D < 0;$ and base on the above analysis, we can conclude that the roots of the quadratic equation are complex or imaginary

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