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Flauer [41]
3 years ago
10

Please help!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Brut [27]3 years ago
5 0

You'll use side-angle-side to prove this.

Side: AB = BC was given

Angle: How do you know that angle ABD = angle CBD?

Side: BD = BD

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Solve 6x(6x) + 11x - 35 = 0
Murljashka [212]
36x^2 + 11x - 35=0\\\\ \frac{-b \pm  \sqrt{ b^2 -4( a)(c)} }{2(a)}\\\\  \frac{-11\pm  \sqrt{11^2 -4(36)(-35)} }{2(36)}\\ \\   \frac{-11\pm  \sqrt{5161 } }{72}\\\\\\ x = 0.8450013919812116\\\\ \text{   } x  = -1.1505569475367672
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3 years ago
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The point M(-6, -4) is translated 2 units right. What are the coordinates of the resulting point, M′?
fredd [130]
B) (-4, -4)

When moving to the right you are moving to a more POSITIVE region on the x-axis; meaning, the y-value (vertical axis) does not get affected unless you’re moving up or down.

Remember: (-6, -4)
X = -6
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If you move 2 units to the right (x-axis) you go from -6 + 2 which equals -4. And again, you’re not moving up and down so your
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7 0
3 years ago
Find the slope of y=5x-7
eimsori [14]

Answer:

the slope is 5

Step-by-step explanation:

5 0
3 years ago
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enot [183]

Answer:

254.47 m or B

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8 0
3 years ago
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What is the domain of the function y= square root x - 5 - 1
IrinaK [193]

Answer:

x\geq 5

Step-by-step explanation:

The function that we have to study in this problem is

y=\sqrt{x-5}-1

The domain of a function is defined as the set of all the possible values of x that the function can take.

For a square-root function, there are some limitations to the possible value of the argument in the root.

In particular, the argument of a square root must be equal or greater than zero, because the square root of a negative number is not defined.

Therefore, in this case, we have to set the following condition for the domain:

x-5\geq 0

And by solving, we get

x\geq 5

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5 0
3 years ago
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