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LuckyWell [14K]

3 years ago

13

PLEASE HELP ASAP (giving 20 points)

1 answer:

slamgirl [31]3 years ago

3 0

The answer would be D

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A. Graph the function ????(x) = 3 cos(2x) + 1 between 0 and 2????.

almond37 [142]

Answer:the awnser is A i beleive not 100% sure

Step-by-step explanation:

3 0

3 years ago

Sara and Paul are on opposite sides of a building that a telephone pole fell on. The pole is leaning away from Paul at

r-ruslan [8.4K]

Answer:

a) See figure attached

b) $x = \frac{sin(124)}{sin(34)} 80.086 = 118.732 ft$

c) $h = 35 sin (59) = 30.0 ft$

So then the heigth for the building is approximately 30 ft

Step-by-step explanation:

Part a

We can see the figure attached is a illustration for the problem on this case.

Part b

For this case we can use the sin law to find the value of r first like this:

$\frac{sin(22)}{35 ft} =\frac{sin(59)}{r}$

$r= \frac{sin(59)}{sin(22)} 35 ft = 80.086ft$

Then we can use the same law in order to find the valueof x liek this:

$\frac{sin(124)}{x ft} =\frac{sin(34)}{80.086}$

$x = \frac{sin(124)}{sin(34)} 80.086 = 118.732 ft$

And that represent the distance between Sara and Paul.

Part c

For this cas we are interested on the height h on the figure attached. We can use the sine indentity in order to find it.

$sin (59) = \frac{h}{35}$

And if we solve for h we got:

$h = 35 sin (59) = 30.0 ft$

So then the heigth for the building is approximately 30 ft

5 0

3 years ago

Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that

aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

$A\cap B=$ {HH}

$B\cap C$ ={HH}

$A\cap C$ ={HH}

P(E)= $\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}$

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

$P(A)=\frac{2}{4}=\frac{1}{2}$

Number of favorable cases to event B=2

Number of favorable cases to event C=2

$P(B)=\frac{2}{4}=\frac{1}{2}$

$P(C)=\frac{2}{4}=\frac{1}{2}$

If the two events A and B are independent then

$P(A)\cdot P(B)=P(A\cap B)$

$P(A\cap)=\frac{1}{4}$

$P(B\cap C)=\frac{1}{4}$

$P(A\cap C)=\frac{1}{4}$

$P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}$

$P(B)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(B)=P(A\cap B)$

Therefore, A and B are independent

$P(B)\cdot P(C)=P(B\cap C)$

Therefore, B and C are independent

$P(A\cap C)=P(A)\cdot P(C)$

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

6 0

3 years ago

42,000 as a multipul of a power of 10

MrRa [10]

Answer:

$4.2 \times {10}^{4}$

Step-by-step explanation:

$42000 = 4.2000 \times \times {10}^{4} \\ = 4.2 \times {10}^{4}$

3 0

3 years ago

The lenght of one <br><br> plz answer right show work or describe

Natasha2012 [34]

Since its a right triangle, you can use a² + b² = c²
one of the legs is a and the other leg is b it doesn't matter which one because its addition and works the same way c needs to be the hypotenuse

so its a² + 48² = 50²
a² + 2304 = 2500
- 2304 -2304
a² = 196
√a² = √196
a = 14

7 0

3 years ago