Answer:
<h3>531,441</h3>
Step-by-step explanation:

Answer:
it is one shape and bc gos strat though
Step-by-step explanation:
Answer:
The first listed equation is the correct equation to solve
The correct answer is: t = 5 seconds
Step-by-step explanation:
Let me mention first that there is an error in the statement that the gravitational pull of the Earth is 16 ft/s^2. It is in fact 32 ft/s^2, and the actual equation uses half of the acceleration multiplied by the square of the variable time, so it gives as final expression :

and we want to find the value/s for "t" that make this equation equal zero (when it reaches the ground and the object just touches the ground. This makes the equation we want to solve:

which solving for "t" becomes:

So we adopt the positive answer (positive time) since the negative value has no physical meaning for this problem.
That is: t = 5 seconds
Label your sides= hypotenuse(h),opposite(o),adjacent(a)
hypotenuse=longest(opposite the right angle)
opposite= opposite the other angle
adjacent= the other side
see which sides are involved
in this case it is adjacent and hypotenuse
so A and H
we have to use the SOHCAHTOA rule
Sin=o/h Cos=a/h Tan=o/a
we use cos because a and h are involved
Cos(15°)=62/x
rearrange the equation to find x
x= 62/cos(15)
put this in your calculator
x= 64.12