Solve the given differential equation dx-(1-x)2dt=0
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1) Slope tell about the steepness of the line.
To find slope we look at the rise and run between 2 points.
attached the graph of line with slope
slope =
=
So slope = 2
2) we have x and y intercepts
x intercept is the point where the line crosses x axis
x intercept at x= 3
y intercept is the point where the line crosses y axis
y intercept at y= 6
3) Linear equation is y= 3x+2
function is f(x) = 3x+2
We can graph it using slope and y intercept
In f(x)= 3x + 2 , slope =3 and y intercept = 2
slope = 3, rise = 3 and run =1
The graph of f(x)= 3x+2 is attached below.
