All categories

3 years ago

Which two number have an absolute value of 2

Mathematics

1 answer:

madam [21]3 years ago

3 0

Answer:2 -2

Step-by-step explanation:absolute value is distance from zero so both of those are the same distance from zero

You might be interested in

Use set builder notation to give a description of each of these sets. a) {0,3,6,9,12} b) {−3,−2,−1,0,1,2,3} c) {m,n,o,p}

attashe74 [19]

Answer:

$\left \{ 0,3,6,9,12 \right \}=\left \{ x;x=3n\,,\,n\,\varepsilon \,W ;\,\,n\leq 4\right \}\\\left \{ -3,-2,-1,0,1,2,3 \right \}=\left \{ x;x=\pm n;\,\,n=0,1,2,3 \right \}\\\left \{ m,n,o,p \right \}=\left \{ x;x \,\,is\,\,an\,\,alphabet\,\,after\,\,l\,\,and\,\,before\,\,q \right \}$

Step-by-step explanation:

The set is a well-defined collection of objects.

Set builder form describes the set by stating the property of each of its elements.

$\left \{ 0,3,6,9,12 \right \}=\left \{ x;x=3n\,,\,n\,\varepsilon \,W ;\,\,n\leq 4\right \}$

W is a set of whole numbers.

$\left \{ -3,-2,-1,0,1,2,3 \right \}=\left \{ x;x=\pm n;\,\,n=0,1,2,3 \right \}$

$\left \{ m,n,o,p \right \}=\left \{ x;x \,\,is\,\,an\,\,alphabet\,\,after\,\,l\,\,and\,\,before\,\,q \right \}$

7 0

3 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex

velikii [3]

Answer:

The maximum value= 36

Minimum value = - 36

Step-by-step explanation:

Given that

f(x, y, z) = 8 x + 8 y + 4 z

h(x,y,z)=4 x² + 4 y² + 4 z² - 36

From Lagrange multipliers

Δf = λ Δh

Δf = < 8 ,8 , 4>

Δh = < 8 x ,8 y , 8 z>

Δf = λ Δh

< 8 ,8 , 4> = < 8 λ x ,8 λ y , 8 λ z>

8 = 8 λ x -------------1

8 = 8 λ y ---- ------2

4 = 8 λ z ----------------3

From equation 1 ,2 and 3

Now by putting the value of x,y and z in the following equation

4 x² + 4 y² + 4 z² = 36

$4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{(2\lambda)^2 }=36$

$\dfrac{4}{\lambda^2 }+ \dfrac{4}{\lambda^2 }+ \dfrac{1}{\lambda^2 }=36$

So the value of λ is

$\lambda =\pm \dfrac{1}{2}$

When λ = 1/2

x = 1 / λ , y=1 / λ , z= 1 /2 λ

x= 2 , y = 2 , z=1

f(x, y, z) = 8 x + 8 y + 4 z

f(2, 2, 1) = 8 x 2 + 8 x 2 + 4 x 1

f(2, 2, 1) =36

When λ = - 1/2

x = 1 / λ , y=1 / λ , z= 1 /2 λ

x= - 2 , y = - 2 , z= - 1

f(x, y, z) = 8 x + 8 y + 4 z

f(-2, -2, -1) = 8 x (-2) + 8 x (-2) + 4 x (-1)

f(-2, -2, -1) = - 36

The maximum value= 36

Minimum value = - 36

7 0

3 years ago

Read 2 more answers

Find the value of x plz :(

lutik1710 [3]

Answer:

stop

Step-by-step explanation:

stop using this app, the chances of you actually getting a helpful response or even one at all are so slim, just pay an actual tutor at this point

6 0

3 years ago

Identify the variables in the graph describe how the variables are related

Alex17521 [72]

The time(h), would be the independent variable and the temperature(C) would be the dependent variable.

3 0

3 years ago

Can someone please help me????? Please I'm not good with Geometry

Otrada [13]

The hurdle and runner form a right triangle (see attached picture) such that

sin(30°) = h / (5 ft)

and

cos(30°) = x / (5 ft)

where h is the height of the hurdle and x is the horizontal distance from where the runner jumps to the hurdle. So

h = (5 ft) sin(30°) = 5/2 ft = 2.5 ft

x = (5 ft) cos(30°) = (5√3)/2 ft ≈ 4.33 ft

6 0

3 years ago