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3 years ago

13

An auditorium has 28 seats in the front row. Each row behind the front has 3 more seats than the row directly in front of it. Ho

w many seats are there in the 11th row?

1 answer:

KIM [24]3 years ago

8 0

Answer:

28+3=31

each seat behind the front seat had 31seats

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A 2-column table with 3 rows. Column 1 is labeled Number of Rows with entries 1, 3, 5. Column 2 is labeled Number of Seats with

Mnenie [13.5K]

Answer:

30

Step-by-step explanation:

One row has 6 seats

<u>3 rows have:</u>

3*6 = 18 seats

<u>5 rows have:</u>

5*6 = 30 seats

A = 30

4 0

2 years ago

Read 2 more answers

Which numner is bigger -24 or -16<br><br>passes helppp

wlad13 [49]

Answer:

-16

Step-by-step explanation:

-16 is a bigger number than -24 because its closer to positive numbers on the number line. Closer to 0 or 1 on the number line.

4 0

2 years ago

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A delivery truck is transporting boxes of two sizes: large and small. The combined weight of a large box and a small box is 60 p

boyakko [2]

Answer:

large: 40 lbs
small: 20 lbs

Step-by-step explanation:

A system of equations can be written for the weights of the boxes based on the relationships given in the problem statement. One equation will be for the total weight of 1 large and 1 small box; the other will be for the total weight of 70 large and 60 small boxes.

Let L and S represent the weights of Large and Small boxes, respectively. The system of equations is ...

L + S = 60 . . . . . . combined weight is 60 lbs

70L +60S = 4000 . . . . weight of boxes in the truck

__

We can solve this by substituting for s in the second equation.

70L +60(60 -L) = 4000

10L = 400 . . . . . . . . . subtract 3600, simplify

L = 40

S = 60 -L = 20

A large box weighs 40 pounds; a small box weighs 20 pounds.

7 0

2 years ago

Select all the points that are on the line through (0 5) and (2 8) A.(5 11) B.(5 10) C.(6 14) D.(30 50) E.(40 60)

mihalych1998 [28]

Answer:

Options C. and D. are correct.

Step-by-step explanation:

Let $(x_1,y_1)=(0,5),\,(x_2,y_2)=(2,8)$

Equation of a line is given by $y-y_1=(\frac{y_2-y_1}{x_2-x_1})(x-x_1)$

$y-5=(\frac{8-5}{2-0})(x-0)\\\\y-5=\frac{3}{2}x\\\\2y-10=3x\\3x-2y+10=0$

Put $(x,y)=(5,11)$

$3(5)-2(11)+10=15-22+10=3\neq 0$

Put $(x,y)=(5,10)$

$3(5)-2(10)+10=15-20+10=5\neq 0$

Put $(x,y)=(6,14)$

$3(6)-2(14)+10=18-28+10=0$

Put $(x,y)=(30,50)$

$3(30)-2(50)+10=90-100+10=0$

Put $(x,y)=(40,60)$

$3(40)-2(60)+10=0\\120-120+10=10\neq 0$

So, points $(6,14),\,(30,50)$ satisfy the equation $3x-2y+10=0$

Therefore,

points $(6,14),\,(30,50)$ lie on the line through $(0,5)$ and $(2,8)$

Options C. and D. are correct.

8 0

2 years ago

Determine whether each expression was simplified correctly.

astra-53 [7]

Answer:

Only b is correctly simplified.

Step-by-step explanation:

3 0

2 years ago