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2 years ago

R + 74 = R - 74 is true for: Please solve for R

Mathematics

1 answer:

Alinara [238K]2 years ago

7 0

Answer:

No solution

Step-by-step explanation:

Because ;

R+74=R-74

R-R=-74-74 —> 0= -148

Or R-R=74+74 —> 0=148

I hope I helped you^_^

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Which equation does the graph of the systems of equations solve? It's a quadratic graph opening down and quadratic graph opening

vodka [1.7K]

Answer:

D. $-x^{2} -2x+3=2x^{2} -8x+3$

Step-by-step explanation:

We are given that,

The graph of the system of equations is a 'quadratic graph opening down and a quadratic graph opening up'.

This means that one quadratic equation will have leading co-efficient positive and other will have leading co-efficient negative.

So, we get that options A and B are discarded.

Further it is provided that the graph intersect at ( 0,3 ) and ( 2,-5 ).

This means that the pair of points must satisfy the given system of equations.

So, according to the options:

C. $-x^{2} -2x+3=2x^{2} -8x-3$

Putting x = 0, gives 3 = -3, which is not possible.

So, option C is dicarded.

D. $-x^{2} -2x+3=2x^{2} -8x+3$

Putting x = 0 gives 3 = 3 and x = 2 gives -5 = -5.

Hence, the graph of the given system solves the equation $-x^{2} -2x+3=2x^{2} -8x+3$ .

7 0

3 years ago

A man starts walking north at 2 ft/s from a point P. Five minutes later a woman starts walking south at 3 ft/s from a point 500

Vedmedyk [2.9K]

Answer:

The rate at which both of them are moving apart is 4.9761 ft/sec.

Step-by-step explanation:

Given:

Rate at which the woman is walking, $\frac{d(w)}{dt}$ = 3 ft/sec

Rate at which the man is walking, $\frac{d(m)}{dt}$ = 2 ft/sec

Collective rate of both, $\frac{d(m+w)}{dt}$ = 5 ft/sec

Woman starts walking after 5 mins so we have to consider total time traveled by man as (5+15) min = 20 min

Now,

Distance traveled by man and woman are $m$ and $w$ ft respectively.

⇒ $m=2\ ft/sec=2\times \frac{60}{min} \times 20\ min =2400\ ft$

⇒ $w=3\ ft/sec = 3\times \frac{60}{min} \times 15\ min =2700\ ft$

As we see in the diagram (attachment) that it forms a right angled triangle and we have to calculate $\frac{dh}{dt}$ .

Lets calculate h.

Applying Pythagoras formula.

⇒ $h^2=(m+w)^2+500^2$

⇒ $h=\sqrt{(2400+2700)^2+500^2} = 5124.45$

Now differentiating the Pythagoras formula we can calculate the rate at which both of them are moving apart.

Differentiating with respect to time.

⇒ $h^2=(m+w)^2+500^2$

⇒ $2h\frac{d(h)}{dt}=2(m+w)\frac{d(m+w)}{dt} + \frac{d(500)}{dt}$

⇒ $\frac{d(h)}{dt} =\frac{2(m+w)\frac{d(m+w)}{dt} }{2h}$ ...as $\frac{d(500)}{dt}= 0$

⇒ Plugging the values.

⇒ $\frac{d(h)}{dt} =\frac{2(2400+2700)(5)}{2\times 5124.45}$ ...as $\frac{d(m+w)}{dt} = 5$ ft/sec

⇒ $\frac{d(h)}{dt} =4.9761$ ft/sec

So the rate from which man and woman moving apart is 4.9761 ft/sec.

3 0

3 years ago

What is the slope of the line? A. 2/5 B. -2/5 C. 5/2 D. -5/2

sergey [27]

Answer:

B. -2/5

Step-by-step explanation:

For a "run" (x change) of 5, the "rise" (y change) is -2 units. Then the slope is ...

slope = rise/run = -2/5

7 0

3 years ago

Read 2 more answers

In mid-day meal scheme 1/ 10 litre of milk is given to each student of a primary school. If 30 litres of milk are distributed ev

nirvana33 [79]

Answer:

300 students

Step-by-step explanation:

To know the number of students, we must divide the total amount of milk spent by the amount spent for each and in this way we will obtain the value we are looking for, like this (both have the same units of L, so there is no problem ):

30 / (1/10) = 300

that is to say that there are a total of 300 students

5 0

3 years ago

The set of numbers that includes the whole numbers and their opposites is called the set of...?

Nookie1986 [14]

Step-by-step explanation:

option C is the answer

hope it helps

7 0

2 years ago