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podryga [215]
3 years ago
7

R + 74 = R - 74 is true for: Please solve for R

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0

Answer:

No solution

Step-by-step explanation:

Because ;

R+74=R-74

R-R=-74-74 —> 0= -148

Or R-R=74+74 —> 0=148

I hope I helped you^_^

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Alecia builds a box in the shape of a cube with an open top. She plans to paint the box. Alecia calculates that there are 256 sq
STALIN [3.7K]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the options to select the required condition from were not listed. So, I will answer on general terms

From the question, we understand that the cube has an open-top and the surface ares is 256 in^2

Let L represents the edge length, the surface area (S) is:

S = 5L^2

Substitute 256 for S

256 = 5L^2

Divide both sides by 5

51.2 = L^2

Take square roots of both sides:

\sqrt{51.2} = L

7.155= L

L=7.16in ---- approximated

The volume of the cube is:

Volume = L^3

Volume = \sqrt{51.2}^3

Volume = 366.3573

Volume = 366.36in^3

<em>So, the edge length of the cube is 7.16 inches and the volume is 366.36 cubic inches</em>

<em />

6 0
3 years ago
Read 2 more answers
Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa
iVinArrow [24]

Given:

Distance between two buildings = 3x^3- x^2 + 7x +100 feet apart.

Distance between highway and one building = 2x^2 + 7x feet.

Distance between highway and second building = x^3 + 2x^2 - 18 feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)

W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18

Combining like terms, we get

W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)

W=2x^3-5x^2+0+118

W=2x^3-5x^2+118

Therefore, the width point highway is 2x^3-5x^2+118.

8 0
3 years ago
Can I plz get help I don’t understand
Rzqust [24]

One clock of any type costs $3.20. a clocks cost 3.2a. w clocks cost 3.2w.

Add 3.2a to 3.2w to find the total cost.

T = 3.2a + 3.2w

T = 3.2(a + w)

Both expressions above are correct answers.

6 0
4 years ago
Factor 20x^2+15x-35 you must show your work
algol [13]

Answer:

5 (x - 1) (4 x + 7)

Step-by-step explanation:

Factor the following:

20 x^2 + 15 x - 35

Factor 5 out of 20 x^2 + 15 x - 35:

5 (4 x^2 + 3 x - 7)

Factor the quadratic 4 x^2 + 3 x - 7. The coefficient of x^2 is 4 and the constant term is -7. The product of 4 and -7 is -28. The factors of -28 which sum to 3 are -4 and 7. So 4 x^2 + 3 x - 7 = 4 x^2 + 7 x - 4 x - 7 = 7 (x - 1) + 4 x (x - 1):

5 7 (x - 1) + 4 x (x - 1)

Factor x - 1 from 7 (x - 1) + 4 x (x - 1):

Answer: 5 (x - 1) (4 x + 7)

5 0
3 years ago
Estimate: 26÷5 <br>A:4 <br>B:30<br>C:20<br>D:5<br>​
tangare [24]

Answer: 5

Step-by-step explanation:

26/5 = 5.2 = 5

6 0
3 years ago
Read 2 more answers
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