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3 years ago

295.6 divided by 10 with the power of 2

Mathematics

2 answers:

madam [21]3 years ago

8 0

Answer:

873.7936

Step-by-step explanation:

295.6 divided by 10 is

29.56.

This can be easily done by moving the decimal up one place to the left. For 29.56 to the power of 2 is really just 29.56 * 29.56

29.56 * 29.56 is

873.7936.

Hope this helps!

stealth61 [152]3 years ago

6 0

Answer:

2.956

Step-by-step explanation:

$\frac{295.6}{10^2}$

= $\frac{295.6}{100}$

= 2.956

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Points B, D, and F are midpoints of the sides of ACE. EC = 32 and BF = 2x - 10. Find the value of x.

Svetlanka [38]

Answer:

Step-by-step explanation:

Remark

This only works if B is between AC and F is between AE

Givens

CE = 32

BF = 1/2 CE Properties of midpoints. BF is parallel to and 1/2 of CE

BF = 1/2 * 32

BF = 16

Equation

2x - 10 = 16 Add 10 to both sides

2x - 10 + 10 = 16 + 10 Combine

2x = 26 Divide by 2

2x/2 = 26/2 Do the division

x = 13

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4 years ago

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Assoli18 [71]

The answer would be D

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3 years ago

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Compute the differential of surface area for the surface S described by the given parametrization.

AysviL [449]

With $S$ parameterized by

$\vec r(u,v)=\langle e^u\cos v,e^u\sin v,uv\rangle$

the surface element $\mathrm dS$ is

$\mathrm dS=\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

We have

$\dfrac{\partial\vec r}{\partial u}=\langle e^u\cos v,e^u\sin v,v\rangle$

$\dfrac{\partial\vec r}{\partial v}=\langle -e^u\sin v,e^u\cos v,u\rangle$

with cross product

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle ue^u\sin v-ve^u\cos v,-ve^u\sin v-ue^u\cos v,e^{2u}\cos^2v+e^{2u}\sin^2v\rangle$

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle e^u(u\sin v-v\cos v),-e^u(v\sin v+u\cos v),e^{2u}\rangle$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{e^{2u}(u\sin v-v\cos v)^2+e^{2u}(v\sin v+u\cos v)^2+e^{4u}}$

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=e^u\sqrt{u^2+v^2+e^{2u}}$

So we have

$\mathrm dS=\boxed{e^u\sqrt{u^2+v^2+e^{2u}}\,\mathrm du\,\mathrm dv}$

8 0

3 years ago

If the length of a rectangle is 27 feet and the perimeter is 116, what is the width?

Kobotan [32]

Answer:

w=31 feet

Step-by-step explanation:

multiply the length that you have been given by 2, and subtract the result from the perimeter. You now have the total length for the remaining 2 sides. This number divided by 2 is the width.

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3 years ago

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Find the value of each variable.

Mrac [35]

Answer:

x = 6

y = 4

Step-by-step explanation:

Apply the angle bisector theorem to solve for x and y respectively.

✔️4/(9 - x) = 8/x

Cross multiply

4*x = 8(9 - x)

4x = 72 - 8x

Add 8x to both sides

4x + 8x = 72

12x = 72

12x/12 = 72/12

x = 6

✔️y/2 = 6/3

Cross multiply

3*y = 6*2

3y = 12

3y/3 = 12/3

y = 4

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3 years ago