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3 years ago

URGENT A measure of the spacing between atoms is: density inertia mass volume

Mathematics

1 answer:

lilavasa [31]3 years ago

7 0

Answer:

inertia

Step-by-step explanation:

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MO and PR are parallel lines. Which angles are alternate interior angles?

Kipish [7]

Answer:

It would be helpful if you show me the figure. Thanks :) !!

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3 years ago

In the statement “If a line is bisected then it is cut into two equal parts”. The hypothesis is “If a line is bisected” and the

tensa zangetsu [6.8K]

Answer:

True

Step-by-step explanation:

The hypothesis of a conditional statement is the "if" part. This means the hypothesis is "If a line is bisected."

The conclusion of a conditional statement is the "then" part. This means the conclusion is "then it is cut into two equal parts."

8 0

3 years ago

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Anne made a recipe for miniature bread loaves that called for StartFraction 7 Over 8 EndFraction of a cup of whole-wheat flour.

Anika [276]

Answer:49/8

Step-by-step explanation:7/8 times 7 is 49/8

6 0

3 years ago

Read 2 more answers

“encontrar la integral indefinida y verificar el resultado mediante derivación”

Oliga [24]

$I=\displaystyle\int\frac x{(1-x^2)^3}\,\mathrm dx$

Haz la sustitución:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{y^3}=\frac1{4y^2}+C=\frac1{4(1-x^2)^2}+C$

Para confirmar el resultado:

$\dfrac{\mathrm dI}{\mathrm dx}=\dfrac14\left(-\dfrac{2(-2x)}{(1-x^2)^3}\right)=\dfrac x{(1-x^2)^3}$

$I=\displaystyle\int\frac{x^2}{(1+x^3)^2}\,\mathrm dx$

Sustituye:

$y=1+x^3\implies\mathrm dy=3x^2\,\mathrm dx$

$\implies I=\displaystyle\frac13\int\frac{\mathrm dy}{y^2}=-\frac1{3y}+C=-\frac1{3(1+x^3)}+C$

(Te dejaré confirmar por ti mismo.)

$I=\displaystyle\int\frac x{\sqrt{1-x^2}}\,\mathrm dx$

Sustituye:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{\sqrt y}=-\frac12(2\sqrt y)+C=-\sqrt{1-x^2}+C$

$I=\displaystyle\int\left(1+\frac1t\right)^3\frac{\mathrm dt}{t^2}$

Sustituye:

$u=1+\dfrac1t\implies\mathrm du=-\dfrac{\mathrm dt}{t^2}$

$\implies I=-\displaystyle\int u^3\,\mathrm du=-\frac{u^4}4+C=-\frac{\left(1+\frac1t\right)^4}4+C$

Podemos hacer que esto se vea un poco mejor:

$\left(1+\dfrac1t\right)^4=\left(\dfrac{t+1}t\right)^4=\dfrac{(t+1)^4}{t^4}$

$\implies I=-\dfrac{(t+1)^4}{4t^4}+C$

4 0

3 years ago

Which expressions are equivalent to -2(5x-3/4)?

kogti [31]

Answer:

-10x+3/2

Hope this helps

6 0

3 years ago