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shtirl [24]
3 years ago
6

If the 2/5 of a number exceeds 1/7 of the same number by 36 then the number is

Mathematics
1 answer:
valkas [14]3 years ago
5 0

Answer:

Below in bold.

Step-by-step explanation:

2/5 x - 1/7 x = 36

14/35 x - 5/35x = 36

9x / 35 = 36

x = 35*36 / 9

x = 35*4 = 140 (answer).

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sad story not my pics got from the internet on gram this is bopy he is about 6 or 7 his brother is using him for clout and makin
Aleks04 [339]

Answer:

lol I'm not reading that entire story but lemme tell you his HAIRCUT is the sad story here. whoever did that to the poor boys hair needs to be put away for LIFE

9 0
3 years ago
What is the maximum value of the picture below?
Cloud [144]

Answer:

y = 4

Step-by-step explanation:

The maximum value occurs at the vertex

vertex = (2, 4 )

when x = 2 the maximum value is y = 4

4 0
2 years ago
HELPP<br> What is the size of the label in square cm??
elena55 [62]

Answer:

226.19

Step-by-step explanation:

area of a cylinder is 2 times pi times radius time height plus 2 times pi times radius squared

radius=6/2=3

height=9

substitute in your values and get 226.19cm squared

4 0
2 years ago
Read 2 more answers
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos &#10;y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
Find the distance between the given points (4,1) and (-5, -2)
anyanavicka [17]

Answer:

3\sqrt{10} units I THINK

Step-by-step explanation:

using the distance formula, -2 - 1 = -3

-3 x -3 = 9

-5 - 4 = -9 x -9 = 81

81 + 9 = 90

sqrt 90 simplified is 3\sqrt{10}.

so im pretty sure that's the answer.

5 0
3 years ago
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