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Ostrovityanka [42]
3 years ago
15

Help anyone can help me do this question,I will mark brainlest.​

Mathematics
1 answer:
Ad libitum [116K]3 years ago
3 0

Answer:

David walks 132m.

Using theorem of pythagoras and the dimensions of the kite to calculate. Refer to the picture.

Hope it helps.

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Simplify. 1/3(1−1/4)^2 please
Strike441 [17]

Answer:

3/16

Step-by-step explanation:

1/3(1-1/4)^2

1/3(3/4)^2

1/3(9/16)

3/16

4 0
3 years ago
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!!!I’ll mark brainlest and it’s worth 30 points, it’s for a math test and i’m really confused.!!!
antoniya [11.8K]
It’s C because 90-55
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2 years ago
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1a/3a + 2 = 11 what does a equal
VashaNatasha [74]
Because in the numerator and denominator of the fraction 1a/3a, you're able to simplify that and get 1/3. There is actually no solution to the problem you're asking. You're unable to find out what (a) equals. 
4 0
3 years ago
Let f(x) = (x − 3)−2. Find all values of c in (1, 7) such that f(7) − f(1) = f '(c)(7 − 1). (Enter your answers as a comma-separ
Sidana [21]

Answer:

This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3

Step-by-step explanation:

The given function is

f(x)=(x-3)^{-2}

When we differentiate this function with respect to x, we get;

f'(x)=-\frac{2}{(x-3)^3}

We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)

This implies that;

0.06-0.25=-\frac{2}{(c-3)^3} (6)

-0.19=-\frac{12}{(c-3)^3}

(c-3)^3=\frac{-12}{-0.19}

(c-3)^3=63.15789

c-3=\sqrt[3]{63.15789}

c=3+\sqrt[3]{63.15789}

c=6.98

If this function satisfies the Mean Value Theorem, then f must be continuous on  [1,7] and differentiable on (1,7).

But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.

 

3 0
3 years ago
The domain of the function given below is the set of all real numbers greater
lisabon 2012 [21]
The answer is A. True
3 0
3 years ago
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