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2 years ago

Help anyone can help me do this question,I will mark brainlest.

Mathematics

1 answer:

Ad libitum [116K]2 years ago

3 0

Answer:

David walks 132m.

Using theorem of pythagoras and the dimensions of the kite to calculate. Refer to the picture.

Hope it helps.

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What is algebra I would really like it if you could help

Sergio039 [100]

Answer:

It is the branch of math that is in charge of dealing with letters known as variables.

Step-by-step explanation:

These variables are used to fill in the place of missing numbers in an equation or solution.Algebra is widely used all over the world in schools.

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2 years ago

Read 2 more answers

Show that √(1-cos A/1+cos A) =cosec A - cot A

Gennadij [26K]

Hi there!

$\sqrt{\frac{1-cosA}{1+cosA}} =$

We can begin by multiplying by its conjugate:

$\sqrt{\frac{1-cosA}{1+cosA}} * \sqrt{\frac{1+cosA}{1+cosA}} = \\\\\sqrt{\frac{(1-cosA)(1 + cosA)}{(1+cosA)(1 + cosA)}} =$

Simplify using the identity:

$1 - cos^2A = sin^2A$

$\sqrt{\frac{(1-cos^2A)}{(1+cosA)^2}} =\\\\\sqrt{\frac{(sin^2A)}{(1+cosA)^2}} =$

Take the square root of the expression:

${\frac{sinA}{1+cosA} =$

Multiply again by the conjugate to get a SINGLE term in the denominator:

${\frac{sinA}{1+cosA} * {\frac{1-cosA}{1-cosA} =\\$

Simplify:

${\frac{sinA(1-cosA)}{1-cos^2A} =$

Use the above trig identity one more:

${\frac{sinA(1-cosA)}{sin^2A} =$

Cancel out sinA:

${\frac{(1-cosA)}{sinA} =$

Split the fraction into two:

${\frac{1}{sinA} - \frac{cosA}{sinA} =$

Recall:

$1/sinA = cscA\\\\cosA/sinA = cotA$

Simplify:

$\frac{1}{sinA} + \frac{cosA}{sinA} = \boxed{cscA - cotA}$

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2 years ago

Solve. Express your answer as a simplified mixed number

Semmy [17]

Stick change flip
5/6 x 10/3 = 50/18 2 14/18 simplify 2 7/9

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2 years ago

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How can I divide 5.19 and 16.8

soldi70 [24.7K]

5.19 / 16.8 = <span>0.30892857142</span>

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3 years ago

Plz help with good answer dont answer saying "I think or " im sorry"

STatiana [176]

r= 9 because 45/5 is 9 and it works the same way for the rest of the problems.

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3 years ago

Help anyone can help me do this question,I will mark brainlest.​

Help anyone can help me do this question,I will mark brainlest.