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AURORKA [14]
3 years ago
10

HELP ME PLS I WILL MARK U BRAINLIEST

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

Answer:

(-\infty , 3]

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Which of the following is the equation of a line that passes through the point (1,4) and is parallel to the x-axis?
Alexandra [31]
A because , well Y=4 and the points y coordinate is 4. And when a line is Y= a certain number, its a horizontal line parallel to x axis
8 0
3 years ago
What is the middle product of (-2x 1)(-3x - 5)? User: Factor 64a2 - 48a + 9.
Nikolay [14]
<span>What is the middle product of (-2x 1)(-3x - 5)
= </span><span>(-2x -1)(-3x - 5)
= 6x^2 + 3x + 10x + 5
= 6x^2 + 13x + 5

So the middle product is 13x.

</span><span>Factor 64a2 - 48a + 9.
</span><span>64a2 - 48a + 9
</span>(8a - 3) (8a - 3)
8 0
4 years ago
300 is 60% of what number?
abruzzese [7]

Answer:

500

Step-by-step explanation:

5 0
3 years ago
Find the x-intercept and the y-intercept of the graph of the equation 7x + 25y = 12. Then graph the equation.
Vikki [24]

Answer: sorry, i couldn't graph it

but the equation was done.

7x+25y =12

                    rearrange it into y=mx+c

it becomes:

25y = -7x + 12

y= -0.28x+12

to find y intercept: x=0

so

y= -0.28*0+12

y=12

to find x intercept, y=0

so

0= -0.28x+12

0.28x = 12

x= 12/0.28

x= 42.857142857142857142857142857143‬

approximately = 43(whole number) or 42.9(one decimal place) or 42.86( 2 decimal places)

5 0
3 years ago
Read 2 more answers
The polynomial equation x^4 + x^3 + x^2 + x + 1 = 0 has zero positive real roots. Please select the best answer from the choices
const2013 [10]

There are zero positive real roots for the given polynomial equation x^4 + x^3 + x^2 + x + 1 = 0. This is explained by Descarte's rule of signs. So, the best choice is T (true).

<h3>What is Descarte's rule of signs?</h3>
  • Descarte's rule of signs tells about the number of positive real roots and negative real roots.
  • The number of changes in signs of the coefficients of the terms of the given polynomial f(x) gives the positive real zeros of the polynomial.
  • The number of changes in signs of the coefficients of the terms of the given polynomial when f(-x) gives the negative real zeros of the polynomial.

<h3>Calculation:</h3>

The given polynomial equation is x^4 + x^3 + x^2 + x + 1 = 0

On applying Descarte's rule of signs,

f(x)=x^4 + x^3 + x^2 + x + 1

Since there are no changes in the signs of the coefficients of any of the terms in the above polynomial, the polynomial has no positive real roots.

f(-x)=(-x)^4+(-x)^3+(-x)^2+(-x)+1\\      = x^4-x^3+x^2-x+1

Since there are four changes in the signs of the coefficients of the terms of the given polynomial when f(-x), the polynomial has 4 negative real roots.

Therefore, the given polynomial equation has zero positive real roots. So, the correct choice is T(true).

Learn more about Descarte's rule of signs here:

brainly.com/question/11590228

#SPJ1

5 0
2 years ago
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