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lyudmila [28]
3 years ago
15

Find the equation of a line that is parallel to the line -3x+2y=10 and goes through the point (0,7).

Mathematics
1 answer:
Delvig [45]3 years ago
6 0

Answer:

  3x -2y = -14

Step-by-step explanation:

The parallel line will have a new constant that can be found by substituting the given point for x and y.

  -3x +2y = -3(0) +2(7) = 14

An equation for the parallel line is ...

  -3x +2y = 14

__

In standard form, the leading coefficient is positive, so the standard form equation is ...

  3x -2y = -14

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Don't understand this at all
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5y + (86 - y) = 86 + 4y
Viefleur [7K]

Answer:

All real values, (-∞, ∞)

Step-by-step explanation:

<u>Step 1:  Distribute</u>

5y + (86 - y) = 86 + 4y

5y + 86 - y = 86 + 4y

<u>Step 2:  Combine like terms</u>

5y + 86 - y = 86 + 4y

4y + 86 = 86 + 4y

<u>Step 3:  Subtract 4y from both sides</u>

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<u>Step 4:  Subtract 86 from both sides</u>

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8 0
3 years ago
Read 2 more answers
What is the GFC of 40 and 60
Svetradugi [14.3K]

Answer:

GCF: 20

Step-by-step explanation:

The thing you want to do is factor both numbers down to their lowest primes.

40:2 * 2 * 2 * 5

60:2 * 2 * 5 * 3

Now underline what is in both sets of primes. I'll bold them. The number that is bolded comes from 2 * 2 * 5 which is 20

The highest common factor is 20

3 0
3 years ago
A sample of eight workers in a clothing manufacturing company gave the following figures for the amount of time(in minutes) need
lilavasa [31]

Answer:

10.108 < \mu < 13.892    

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

We have the following distribution for the random variable:

X \sim N(\mu , \sigma=0.45)

And by the central theorem we know that the distribution for the sample mean is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

2) Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=12

The sample deviation calculated s=2.268

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=8-1=7

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,7)".And we see that t_{\alpha/2}=2.36

Now we have everything in order to replace into formula (1):

12-2.36\frac{2.268}{\sqrt{8}}=10.108    

12+2.36\frac{2.268}{\sqrt{8}}=13.892

So on this case the 95% confidence interval would be given by (10.108;13.892)

10.108 < \mu < 13.892    

7 0
3 years ago
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