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jekas [21]
2 years ago
11

What 124.2÷9 step-by-step explanation please help !! ( long division ..”

Mathematics
1 answer:
Andre45 [30]2 years ago
5 0

Answer: 13.8

Step-by-step explanation:

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30 POINTS AND I'LL MARK BRAINLIEST IF ANSWERD ASAP! Upload your 500-word report including your article critiques answering the f
Vlad [161]

Is there an article or a text that you have to do this off of??

4 0
2 years ago
{24, 95, 76, 60, 15, 48, 80, 75}<br> a.<br> Mean =<br> b.<br> Median<br> c.<br> Mode =
sp2606 [1]

Answer:

a)59.125, b)67.5, c)None

Step-by-step explanation:

Mean = All values added up and divided by the number of values
\frac{24+95+76+60+15+48+80+75}{8}

Median = Put all numbers in order from least to most and use the middle one, if there are two, use the mean of those two
15, 24, 48, 60, 75, 76, 80, 95. The middle ones are 60 & 75 so \frac{60+75}{2}

Mode = The number that repeats more times. In this case none of them repeat.

8 0
2 years ago
Find any points of discontinuity for each rational function. Sketch a graph. Describe any verticals or horizontal asympyoyes and
AVprozaik [17]
For
  y = (x^2 -4)/((x +2)(x^2 -49))
the numerator factors to (x -2)(x +2), so the factor of (x +2) will cancel with that in the denominator, leaving
  y = (x -2)/(x^2 -49)

There are points of discontinuity at the hole, x=-2, and at each of the vertical asymptotes, at x=-7, +7.
The horizontal asymptote is y=0.

5 0
3 years ago
Which coefficient matrix represents a system of linear equations that has a unique solution ?
finlep [7]

Answer:

Option C

Step-by-step explanation:

We are given a coefficient matrix along and not the solution matrix

Since solution matrix is not given we cannot check for infinity solutions.

But we can check whether coefficient matrix is 0 or not

If coefficient matrix is zero, the system is inconsistent and hence no solution.

Option A)

|A|=\left[\begin{array}{ccc}4&2&6\\2&1&3\\-2&3&-4\end{array}\right] =0

since II row is a multiple of I row

Hence no solution or infinite

OPtion B

|B|=\left[\begin{array}{ccc}2&0&-2\\-7&1&5\\4&-2&0\end{array}\right] \\=2(10)-2(10)=0

Hence no solution or infinite

Option C

\left[\begin{array}{ccc}6&0&-2\\-2&0&6\\1&-2&0\end{array}\right] \\=2(36-2)=68

Hence there will be a unique solution

Option D

\left[\begin{array}{ccc}5&10&5\\4&1&4\\-1&-2&-1\end{array}\right] \\=2(10)-2(10)=0=0

(since I row is -5 times III row)

Hence there will be no or infinite solution

Option C is the correct answer



4 0
2 years ago
Read 2 more answers
Multiply (x+4)(x-3).What is the product?
il63 [147K]
Since you have to distribute both numbers, you'll end up with x^2-3x+4x-12 then simplify and it is x^2+x-12
8 0
2 years ago
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