It all depends on the species, some lose all of their leaves for part of the year while others lose their leaves before the next growing season, retaining some during winter or dry periods.
I think its (Haploid with 46) but i am not sure sorry
Answer:
Check down
Explanation:
Gymnosperms, like angiosperms (the flowering plants), differ from seedless plants (like mosses and ferns) in not requiring water for sperm to swim in to reach the egg. This means that the movement of pollen (male gamete) to ovule (female gamete) in seed plants relies on airborne transport, not water transport.
<h2>Active and Passive Immunity</h2>
Explanation:
- Immunity can be obtained distinctly and Recovery from clinical tetanus doesn't bring about assurance against future disease by <em>active or passive immunization</em> and recovery from the clinical<em> for example, immunization, immunoglobulin treatment, or move of maternal antibodies through the placenta</em>
- Active inoculation stimulates the <em>immune system to deliver antibodies against a specific irresistible specialist</em>
- <em>Active immunity</em> can emerge normally, as when somebody is presented to a pathogen.<em> For example,</em> a person who recuperates from a first instance of the measles is <em>insusceptible to advance immunity</em>
Answer:
(a) number of strands (n) = time (t) ÷ proportionality constant (k)
(b) The time needed for the bacterial to double its initial size is 3.36 hours.
Explanation:
(a) Let the rate (time) be represented by t and the amount (number) of strands of bacteria be represented by n
t is proportional to n, therefore, t = kn (k is the proportionality constant)
Since t = kn, then, n = t/k
(b) Initial amount of strands = 300
Amount of strands after 2 hours = 300 + (300 × 20/100) = 300 + 60 = 360
k = t/n = 2/360 = 0.0056 hour/strand
Double of the initial size is 600 (300×2 = 600)
Time (t) needed for the bacterial to double its initial size = kn = 0.0056×600 = 3.36 hours
