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Bezzdna [24]
3 years ago
15

Abcdefghijklmnopqrstuvwxyz

Mathematics
1 answer:
Mashutka [201]3 years ago
3 0

Answer:

now i know my abc's

Step-by-step explanation:

next time YOU BETTER SING WITH ME

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Which is lowest; Brand A: 240 mg sodium for 1/3 pickle or Brand B: 325 mg sodium for 1/2 pickle.
Ainat [17]
Brand A is. Just divide 100 (100% of a pickle) by each number, so 100 divided by 240 and 100 by 325. Then you multiply them by the fraction of 100, which 1/3 is 33.3% and 1/2 is 50%. It comes very close but A is the lowest. 
8 0
3 years ago
Describe how to approximate the value of an irrational number
Vesna [10]
I would either round it to the 10th or 100th place.
4 0
4 years ago
Help please I will give brainleist
Natali5045456 [20]

Answer:

The answer is 80%

8 0
3 years ago
Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
4 years ago
camilla paid $1.15 per pound for x pounds of tomatoes. She paid for her tomatoes with $10 and received $4.48 in change. How many
Alika [10]

Answer:

x=4.8\ pounds

Step-by-step explanation:

Let

x-----> the number of pounds of tomatoes Camilla bought

we know that

The equation that represent this situation is equal to

1.15x=10-4.48

Solve for x

1.15x=5.52

x=5.52/1.15

x=4.8\ pounds

5 0
3 years ago
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