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statuscvo [17]
3 years ago
11

A rectangle has an area of 6x ^ 2 + 7x - 3 square units. Which of the following could represent the perimeter of the rectangle i

n terms of ?
Mathematics
1 answer:
Marina CMI [18]3 years ago
8 0
I got a hold of me and her back on the number so i and she said she was ok
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The radius of circle C is 6 units and the measure of central angle ACB is StartFraction pi Over 2 EndFraction radians. What is t
monitta

Answer:

Given: The radius of circle C is 6 units and the measure of central angle ACB is StartFraction pi Over 2 EndFraction radians.

What is the approximate area of the entire circle?

113 square units

What is the approximate area of the entire sector created by central angle ACB?

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What is the approximate area of the shaded region only?

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3 years ago
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Write a function in terms of t that represents the situation.
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S(t) = S0·(1 + rate)t<span>S(t) = salary at year t
<span>S0 = starting salary = $35,000
</span>rate = 4% = 0.04
<span>t = years</span></span>
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3 years ago
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So I need help with 1 over x minus 8 so like 1/x-8 this is a negative exponent
Trava [24]

Answer and Step-by-step explanation:

one divided by (in parentheses) x minus eight should look like this:

\frac{1}{x-8}

This is a graph of this expression.

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8 0
2 years ago
Someone help please i am so bad at point slope stuff
Fynjy0 [20]
<span>1) Write the point-slope form of the equation of the horizontal line that passes through the point (2, 1). y = 1/2x

2)Write the point-slope form of the equation of the line that passes through the points (6, -9) and (7, 1). 
m = (-9 - 1) / (6 - 7) = -10/-1 = 10
y + 9 = 10 (x - 6)
y = 10x - 69

3) A line passes through the point (-6, 6) and (-6, 2). In two or more complete sentences, explain why it is not possible to write the equation of the given line in the traditional version of the point-slope form of a line. 

4)Write the point-slope form of the equation of the line that passes through the points (-3, 5) and (-1, 4).
m = (5 - 4) / (-3 - -1) = 1/-2
y - 5 = (-1/2) (x +3)
y = (-1/2)x + 7/2

5) Write the point-slope form of the equation of the line that passes through the points (6, 6) and (-6, 1).
m = (6-1)/(6 - -6) = 5 / 12
y - 6 = (5/12) (x-6)
y = (5/12)x + 17 / 2

6) Write the point-slope form of the equation of the line that passes through the points (-8, 2) and (1, -4).
m = (2 - -4)  / (-8 -1) = 6 / -7
y - 2 = (-6/7) (x + 8)
y = (-6/7)x - 50 / 7


7) Write the point-slope form of the equation of the line that passes through the points (5, -9) and (-6, 1).
m = (-9 - 1) / (5 - -6) = -10 / 11
y + 9 = (-10 / 11) (x - 5)
y = (-10 / 11)x -49/11

</span>
3 0
3 years ago
Solve the equation for all values of x.<br> (8x+9)(49x^2-100)=0
Liono4ka [1.6K]

Answer:

x = \frac{-9}{8} , \frac{-10}{7} , \frac{10}{7}

Step-by-step explanation:

8x+9=0

8x=-9

x = \frac{-9}{8}

or

49x^{2}-100 = 0

(7x)^{2} -10^{2} =0,

(7x+10)(7x-10)=0

7x+10=0, 7x-10=0

7x=-10, 7x=10

x=-\frac{-10}{7}, x = \frac{10}{7}

4 0
2 years ago
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