Answer:
410? I don't know. Sorry if it is wrong.
Answer:
the answer is 28 if you multiply if not 30
we know that
The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.
The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.
If the probability that any one egg has 1/6 chance of salmonella
then
the probability that any one egg will not have salmonella = 5/6.
Therefore
for all 5 to not have salmonella
= (5/6)^5 = 3125 / 7776
= 0.401877 = 0.40 to 2 decimal places
REMEMBER this is the probability that NONE have salmonella
Therefore
the probability that at least one does = 1 - 0.40
= 0.60
the answer is
0.60 or 60%
The equation would be:
y = 3x + 15
1) Table: It is pretty easy to do so, just plug in 0, 1, 2, 3, etc. for x and solve for y
2) graph (find slope): slope would be 3 shells/day that has a y-intercept of 15
3) you already defined the variables
4) 3(5)+15 = 15+15 = 30 seashells
I hope this helps!
