Answer:
Step-by-step explanation:
B
The equation of any circle is
(x - a)^2 + (y - b)^2 = radius^2 where our center is (a, b)
Therefore, our equation is as follows.
(x + 2)^2 + (y - 3)^2 = 16
Okay so here we have the function f(x)=3x-6 if you plug in -2 to x you get -12 if you plug in -1 you get -9 and if you plug in 0 you get -6 add three each time
Answer:
3x^2−4x−4
Step-by-step explanation:
3x^2−8x−2+4x−2
=3x^2+−8x+−2+4x+−2
3x^2+−8x+−2+4x+−2
=(3x^2)+(−8x+4x)+(−2+−2)
=3x^2+−4x+−4
4x² + 2x - 30 = 0
<span>
factor out the GCF:
</span>2(2x² + x - 15) = 0
<span>
factor the trinomial completely:
2x</span>² + x - 15 = 0
2x² + 6x - 5x - 15 = 0
2x(x + 3) - 5(x + 3) = 0
(2x - 5)(x + 3) = 0
<span>use the zero product property and set each factor equal to zero and solve:
2x - 5 = 0 or x + 3 = 0
2x = 5 x = -3
x = 2.5
</span><span>The roots of the function are x=-3, x=2.5</span>
