Ln(xy) - 2x =0
slope of the tangent line = derivative of the function
[ln(xy)]' = [2x]'
[1/(xy)] [y + xy'] = 2
y + xy' = 2(xy)
xy' = 2xy - y =y(2x-1)
y' = y(2x-1)/x
Now use x = -1 to find y and after to find y'
ln(xy) = 2x
x=-1
ln(-y) =-2
-y = e^-2
y = - e^-2
y' = [-e^-2][2(-1)-1]/(-1) = [e^-2](-2-1)= [e^-2](-3) = - 3e^-2
Answer: option 6. from the list
Given the following values for a quadratic function, which is the graph of the function? (–1, 0), (0, 3), (1, 4), (2, 3), (3, 0)
Firdavs [7]
Answer:
The function of the graph is f(x) = - x² + 2x + 3
Step-by-step explanation:
Using the value of the graph we can say that the the function is negative x² because there are x-intercepts and the y-intercept if above 0.
Using the x-intercepts we can form the function of the graph:
-(x + 1)(x - 3) - we have a negative in front of the two brackets because the function is a negative. Now we multiply out the brackets and the negative at the end:
-(x² - 2x - 3)
- x² + 2x + 3 - So the function of the graph is:
f(x) = - x² + 2x + 3
Answer
6/5 and 17/8
Step-by-step explanation:
1 1/5 = 6/5
1= 5/5 + 1/5 = 6/5
2 1/8 = 17/8
2 = 16/8 + 1/8 = 17/8
Answer:
angle 1 IS the given angle
angle 2 is 180 minus the given angle
Step-by-step explanation:
dont believe me? get out a ruler