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Tamiku [17]
3 years ago
8

Match the addition and subtraction problems to their solutions:

Mathematics
2 answers:
ololo11 [35]3 years ago
8 0

Answer:

1. B

2.c

3. E

4.d

5.A

Step-by-step explanation:

lys-0071 [83]3 years ago
3 0

Answer:

we conclude that:

5/7 - 3/7:     B 2/7

1/6+3/6:      C 2/3

1/2+1/4:       E 3/4

1/5+1/2:       D 7/10

1/6-1/8:       A 1/24

Step-by-step explanation:

1)

Given the expression

\frac{5}{7}-\frac{3}{7}

Apply the fraction rule:   \frac{a}{c}-\frac{b}{c}=\frac{a-b}{c}

\frac{5}{7}-\frac{3}{7}=\frac{5-3}{7}

Add the numbers:  5-3=2

          =\frac{2}{7}

2)

Given the expression

\frac{1}{6}+\frac{3}{6}

Apply the fraction rule:  \frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}

\frac{1}{6}+\frac{3}{6}=\frac{1+3}{6}

Add the numbers:   1+3=4

         =\frac{4}{6}

Cancel 4/6: 2/3

         =\frac{2}{3}

3)

Given the expression

\frac{1}{2}+\frac{1}{4}

Lease common multiplier of 2, 4: 4

Adjust fractions based on LCM

\frac{1}{2}+\frac{1}{4}=\frac{2}{4}+\frac{1}{4}

Apply the fraction rule:  \frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}

\frac{2}{4}+\frac{1}{4}=\frac{2+1}{4}

Add the numbers:  2+1=3

         =\frac{3}{4}

4)

\frac{1}{5}+\frac{1}{2}

Lease common multiplier of 5, 2: 10

Adjust fractions based on LCM

\frac{1}{5}+\frac{1}{2}=\frac{2}{10}+\frac{5}{10}

Apply the fraction rule:  \frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}

\frac{2}{10}+\frac{5}{10}=\frac{2+5}{10}

Add the numbers: 2+5 = 7

=\frac{7}{10}

5)

Given the expression

\frac{1}{6}-\frac{1}{8}

Lease common multiplier of 6, 8: 24

Adjust fractions based on LCM

\frac{1}{6}-\frac{1}{8}=\frac{4}{24}-\frac{3}{24}

Apply the fraction rule:   \frac{a}{c}-\frac{b}{c}=\frac{a-b}{c}

\frac{4}{24}-\frac{3}{24}=\frac{4-3}{24}

             =\frac{1}{24}

Therefore, we conclude that:

5/7 - 3/7:     B 2/7

1/6+3/6:      C 2/3

1/2+1/4:       E 3/4

1/5+1/2:       D 7/10

1/6-1/8:       A 1/24

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<span><u><em>Answer:</em></u>
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<u><em>Explanation:</em></u>
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For the given, we want to find </span>\frac{1}{5}<span> of 45.
<u><em>This can be computed as follows:</em></u>
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