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PolarNik [594]
3 years ago
11

The product of a number and ten decreased by one

Mathematics
1 answer:
Artemon [7]3 years ago
7 0

Answer:

Do you mean an equation? if so, then i think youd use this:

Step-by-step explanation:

(x+10)-1

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110 meters of fencing are used to fence a rectangular pasture of 750 square meters of farmland. If the length of the pasture is
omeli [17]

Answer:

<h3>25m</h3>

Step-by-step explanation:

Perimeter of the rectangular pasture P = 2(L+W)

Area A = LW

L is the length

W is the width

Given

Perimeter = 110m

Area = 750m

If the length of the pasture is 40m longer than the width, then L = W+40

110 = 2L+2w

55 = L+W .....1

750 = LW.....2

Solving simultaneously

from 1; L = 55-W

substitute into 2;

750 = (55-W)W

750 = 55W-W²

-W²+55W -750 = 0

W²-55W+750 = 0

(W²-25W)-(30W+750) = 0

W(W-25)-30(W-25) = 0

(W-25)(W-30) = 0

W-25 = 0 and W-30 = 0

w = 25m and 30m

Since L = 55-W

L = 55-25 = 30m and;

L = 55-30 = 25m

Since we are told that length id longer than the width then, the width we are going to use is 25m

7 0
3 years ago
What is the area of the shape?
Nimfa-mama [501]
A = (14)(18) + 1/2(18)(13)
A = 252 + 117
A = 369

answer
369 m^2
8 0
4 years ago
What the decimal place for 423
Oksana_A [137]
Four and 23 hundredths
4.23

I hope this helps! :D (Sorry if these are wrong.)
6 0
3 years ago
Joan has earned grades of 88, 94, 92, and 98 on math tests so far. What must her next grade be to give her an average grade of 6
Ira Lisetskai [31]

Answer:

see the explanation

Step-by-step explanation:

Let

x ------> the next grade

we know that

To find the average grade sum the grades by the number of math test

so

60=\frac{(88+94+92+98+x)}{5}

solve for x

Combine liker terms in the right side  

60=\frac{(372+x)}{5}

Multiply by 5 both sides

300=372+x

Subtract 372 both sides

300=372+x

x=-72 -----> this is not make sense

The grade cannot be a negative number

so

For x=0

The minimum average grade is

\frac{(372)}{5}=74.4

3 0
3 years ago
Which two values of x are roots
FrozenT [24]
The answer is C. 

To solve these types of equations you first need to make sure that you equation is equal to 0. In this case all of the numbers are already on the same side so no work needs to be done there. Then we can get a, b and c values for the quadratic equation by looking at the coefficients. 

a = 4 (number attached to x^2)
b = -6 (number attached to x)
c = 1 (number with no variable attached)

Now we can put this into the quadratic equation. 

\frac{-b +/-  \sqrt{ b^{2} -4ac} }{2a}

\frac{6 +/- \sqrt{ -6^{2} -4(4)(1)} }{2(4)}

\frac{6 +/- \sqrt{20} }{8}
6 0
4 years ago
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