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3 years ago

12

What the decimal place for 423

1 answer:

Oksana_A [137]3 years ago

6 0

Four and 23 hundredths
4.23

I hope this helps! :D (Sorry if these are wrong.)

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What is 0.000000986 in scientific notation?<br> ____x10---

Lilit [14]

$0.000000986 = 986 \times 10^{-9}=\boxed{ 9.86 \times 10^{-7}}$

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3 years ago

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Is this all right because my homework is tomorrow

Leto [7]

Yeah, its all correct

7 0

3 years ago

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What is the volume of a cone that has a diameter of 18 centimeters and a height of 12 centimeters?

Leokris [45]

Step-by-step explanation:

❀ $\underline{ \underline{ \text{Given}}} :$

Diameter of a cone ( d ) = 18 cm
Height of a cone ( h ) = 12 cm
Radius of a cone ( r ) =
$\sf{ \frac{18}{2} = 9 \: cm}$

❀ $\underline{ \underline{ \text{To \: find}}} :$

Volume of a cone ( V )

✏ $\underline{ \underline{ \text{Solution}}} :$

$\boxed{ \sf{Volume \: of \: a \: cone = \pi \: {r}^{2} \: \frac{h}{3}}}$

Plug the values and then multiply !

→ $\tt{ \frac{22}{7} \times {9}^{2} \times \frac{12}{3}}$

→ $\tt{3.14 \times 81 \times 4}$

→ $\tt{1017.36 \: {cm}^{3}}$

$\pink{ \boxed{ \boxed{ \tt{Our \: final \: answer : 1017.36 \: {cm}^{3}}}} }$

Hope I helped ! ツ

Have a wonderful day / night ! ♡

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7 0

3 years ago

Which number line shows point A plotted at -7?

Hatshy [7]

Answer:

The third number line.

Hope this helps and have a great day!

And please mark me brainliest if you can :)

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2 years ago

A steady wind blows a kite due west. The kite's height above ground from horizontal position x = 0 to x = 80 ft is given by y =

GaryK [48]

Answer:

The distance travelled by the kite is 122.8 ft ( approx )

Step-by-step explanation:

Here, the given function,

$y=150-\frac{1}{40}(x-50)^2$

Differentiating with respect to x,

$y'=-\frac{1}{20}(x-50)$

∵ arc length of a curve is,

$L=\int_{a}^{b} \sqrt{1+y'^2}dx$

Where, y shows the height of the curve for a ≤ x ≤ b,

Thus, the arc length of the given curve is,

$L=\int_{0}^{80} \sqrt{1+(-\frac{1}{20}(x-50)^2}dx$

Put $-\frac{1}{20}(x-50)=tan\theta$

$\implies -dx=-20 sec^2\theta d\theta$

$\implies L=-20\int_{0}^{80} \sqrt{1+tan^2\theta}sec^2\theta d\theta$

$=-20\int_{0}^{80} (sec \theta ) sec^2\theta d\theta$

$=-20\int_{0}^{80} (sec \theta ) sec^2\theta d\theta$

By integration by parts,

$=|-\frac{20}{2}(sec \theta tan\theta +ln|sec\theta +tan\theta |) |^{x=80}_{x=0}$

If x = 80, $tan \theta = -\frac{1}{20}(30-50)=\frac{3}{2}$

$sec \theta = \frac{\sqrt{13}}{2}$

$\implies \theta = \frac{1}{20}(0-50)=\frac{5}{2}$

$sec \theta = \frac{\sqrt{29}}{2}$

Thus, the length of the curve is,

$=-10(\frac{\sqrt{13}}{2}(-\frac{3}{2}) +ln|\frac{13}{2}-\frac{3}{2}|) + 10(\frac{5\sqrt{29}}{4} + ln |\frac{29}{2} + \frac{5}{2} |)$

$\approx 122.8\text{ feet}$

8 0

3 years ago