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Vanyuwa [196]
2 years ago
8

III

Mathematics
1 answer:
irakobra [83]2 years ago
3 0

Answer:

101in

Step-by-step explanation:

9*5=45

9*4=36

5*4=20

45+36+20=101

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Using the proportion 2/5=y/100 which equation can be used to find the value of Y​
natulia [17]
2/5 = y/100
40/100 = y/100
Y=40
4 0
3 years ago
The cost of 20⅕ oranges is rs 300,what is the cost of a kg oranges?​
JulijaS [17]

Answer:

weight not defined

Step-by-step explanation:

The cost of 20⅕ oranges is rs 300 ,what is the cost of a kg oranges?

HOW ARE WE SUPPOSE TO KNOW THE WEIGHT IF ONLY THE PRICE IS GIVEN

5 0
2 years ago
In the equation x^2+10x+24=(x+a)(x+b), b is an integer. Find algebraically all possible values of b
Vinil7 [7]
(x+4)(x+6)
(x+6)(x+4) 

8 0
3 years ago
Three consecutive odd integers have a sum of 27. Find the integers.
jek_recluse [69]

\sf \bf {\boxed {\mathbb {GIVEN:}}}

Sum of three consecutive odd integers = 27

\sf \bf {\boxed {\mathbb {TO\:FIND:}}}

The values of the three integers.

\sf \bf {\boxed {\mathbb {SOLUTION:}}}

\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}

\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}

Let us assume the three consecutive odd integers to be x, (x+2) and (x+4).

As per the condition, we have

Sum \:  \:  of \:  \:  the  \:  \: three \:  \:  consecutive \:  \:  odd \:  \:  integers  = 27

➺ \: x + (x + 2) + (x + 4) = 27

➺ \: x + x + 2 + x + 4 = 27

Now, collect the like terms.

➺ \: (x + x + x) + (2 + 4) = 27

➺ \: 3x + 6 = 27

➺ \: 3x = 27 - 6

➺ \: 3x = 21

➺ \: x =  \frac{21}{3} \\

➺ \: x = 7

Therefore, the three consecutive odd integers whose sum is 27 are \boxed{  7  }, \boxed{ 9   } and \boxed{ 11   } respectively.

\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}

⇢ 7 + 9 + 11 = 27

⇢ 27 = 27

⇢ L. H. S. = R. H. S.

\sf\blue{Hence\:verified.}

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}

4 0
3 years ago
Solve the equation using the quadratic formula
amm1812

Answer:

Step-by-step explanation:

Rewrite this quadratic equation in standard form:  2n^2 + 3n + 54 = 0.  Identify the coefficients of the n terms:  they are 2, 3, 54.

Find the discriminant b^2 - 4ac:  It is 3^2 - 4(2)(54), or -423.  The negative sign tells us that this quadratic has two unequal, complex roots, which are:

     -(3) ± i√423        -3 ± i√423

n = ------------------- = ------------------

             2(2)                      4

3 0
2 years ago
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