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3 years ago

Which of the following describes the following graph?

Mathematics

1 answer:

pychu [463]3 years ago

8 0

Answer:

The correct answer option is B. both a function and a relation.

Step-by-step explanation:

We are given a from from which we can see that for each input we have exactly one output.

This means that we have a function because each element in the domain is matched with exactly one element in the range.

It is also a relation since each input related to the out put in some way.

Therefore, the correct answer option is B. both a function and a relation,

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What are the zeros of f(x)=x^2-10+25

BartSMP [9]

Answer:
-5

Explanation:
Because it’s right

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3 years ago

Does this mean that A is the home or????

alexira [117]

Where the line segment A starts is home

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3 years ago

Is (-3,4) a solution of the inequality y> - 2x – 3?

jeyben [28]

Answer:

(-3, 4) is a solution

Step-by-step explanation:

The point (-3, 4) is inside the shaded area of the graph, so is a solution.

You can check in the inequality

y > -2x -3

4 > -2(-3) -3 . . . . substitute for x and y

4 > 3 . . . . . . . true; the given point is a solution

8 0

3 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$

After simplification and cancellation we get

= $\frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6$

on calculation , we get

= $\frac{124,416}{5} + \frac{864}{3} + 180$

On L.C.M 15

= $\frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}$

= 25 351.2 units²

Conclusion:-

The area of the region between the graph of the given function and the x-axis = 25,351 units²

6 0

3 years ago

When is a lower annual interest fee better than a low annual fee

sertanlavr [38]

hope it helps.........

4 0

3 years ago

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