The probability of occurrence for the events A, B and C is; 1/4.
<h3>What is the probability of occurrence of.the described events?</h3>
For the first event A in which case, there's no odd number on the first two rolls, the possible events are; EEE and EEO. Consequently, the required probability is;
Event A = 2/8 = 1/4.
For the event B in which case, there's an even number on both the first and last rolls; the possible events are; EEE and EOE. Consequently, the required probability is;
Event B = 2/8 = 1/4.
For the event C in which case, there's an odd number on each of the first two rolls; the possible events are; OOO and OOE. Consequently, the required probability is;
Event C = 2/8 = 1/4.
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Answer:
the standard form of the equation is: a. y=7x^2-42x+67
Given:
To find:
The obtuse angle between the given pair of straight lines.
Solution:
The slope intercept form of a line is
...(i)
where, m is slope and b is y-intercept.
The given equations are
On comparing these equations with (i), we get
Angle between two lines whose slopes are 
is
Putting and , we get
Now,
and 
and 
and 
, so it is an obtuse angle and 
, so it is an acute angle.
Therefore, the obtuse angle between the given pair of straight lines is 120°.
Answer:
2,065 tangerines
Step-by-step explanation:
4t = 8,260
t = tangerines
hope this helps :)
Answer:
75.36
Step-by-step explanation:
bc it sinple math if you think about it
