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STatiana [176]
3 years ago
13

PLEASE HELP ME

Mathematics
1 answer:
Marianna [84]3 years ago
7 0
So 70 divided by 2 is 35 so 35 minutes
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Find the volume of a prism. The area of the pentagonal base is (124/tan36°)m² . It’s height is 13 m. If necessary, round your an
lara [203]

Answer:

24.56

Step-by-step explanation:

5 0
3 years ago
I need help in math ;pmdjew2kedfheyuwikejhuwiqo
Licemer1 [7]

Answer:

30/343

Step-by-step explanation:

to find the volume of a rectangle you multiply all three fraction

5/7*3/7*2/7

5/7*3/7=15/49

15/49*2/7=30/343

30/343

5 0
3 years ago
Last year, there were 148 pies baked for the bake sale. This year, there were c pies baked. Using c, write an expression for the
solniwko [45]

\huge{\boxed{c+148}}

We need to find the number of pies baked in years 1 and 2.

There were 148 pies baked in year 1. 148

There were c pies baked in year 2. 148+c

Rearrange the terms so the variable is first. c+148

5 0
3 years ago
Read 2 more answers
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
If m(x) = x2 + 3 and n(x) = 5x + 9, which expression is equivalent to (mn)(x)?
Ilia_Sergeevich [38]
For this case we have the following functions:
 m (x) = x ^ 2 + 3&#10;&#10;n (x) = 5x + 9
 Multiplying both functions, we obtain an expression equivalent to (mn) (x).
 We have then:
 (mn) (x) = m (x) n (x)&#10;
 Substituting values we have:
 (mn) (x) = (x ^ 2 + 3) (5x + 9)&#10;
 Rewriting the expression we have:
 (mn) (x) = (5x ^ 3 + 15x) + (9x ^ 2 + 27)&#10;&#10;(mn) (x) = 5x ^ 3 + 9x ^ 2 + 15x + 27
 Answer:
 
An expression that is equivalent to (mn) (x) is:
 (mn) (x) = 5x ^ 3 + 9x ^ 2 + 15x + 27
7 0
3 years ago
Read 2 more answers
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