A ball is thrown from an initial height of 6 feet with an initial upward velocity of 40ft/s . The ball's height h(in feet) after t seconds is given by the following. h=6+40t-16t^2 Find all values of t for which the ball's height is 28feet. Round your answer(s) to the nearest hundredth.
The answer to this question is true
Answer:
A) (4.0252, 4.0448).
B) (4.0331, 4.0369).
C) If i saw a sample mean of 4.020, i would conclude that the sample came from a population that did not have
a population mean equal to 4.035
Step-by-step explanation:
A) We know that an approximate 95% confidence interval for the item in question is given by the equation; ± 1.96σ
Now, since we have a mean of 4.035 mm and a standard deviation of 0.005 mm, we can solve;
± 1.96 = 4.035 ± (1.96 × 0.005) =4.035 ± (0.0098)
= 4.0252 or 4.0448 and it can be written as;(4.0252, 4.0448).
B) . We also know that In the large-sample case, a 95% confidence interval estimate for the population mean is given by the formula;
± ((1.96)/
√
)
Thus, if we solve, we get;
= 4.035 ± (1.96 ×
0.005
)/√25
= 4.035 ± 0.0019
or (4.0331, 4.0369).
c. If i saw a sample mean of 4.020, i would conclude that the sample came from a population that did not have
a population mean equal to 4.035 because it doesn't fall into the range of confidence intervals we got earlier.
All it did was it counter clock wise rotated to make the shape look like it’s a mirror