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3 years ago

It takes 212121 minutes for 555 people to paint 777 walls. How many minutes does it take 333 people to paint 555 walls?

Mathematics

1 answer:

Papessa [141]3 years ago

3 0

Solution: We are given that:

5 people can paint 7 walls in 21 minutes

Therefore, 1 person can paint 7 walls in $21 \times 5=105$ minutes

Which means 1 person can paint 1 wall in $\frac{105}{7} =15$ minutes

Now, 3 people can paint 1 wall in $\frac{15}{3} =5$ minutes

Therefore, 3 people can paint 5 walls in $5 \times 5=25$ minutes

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30 POINTS TO WHOEVER HELPS WITH THIS I NEED IT ASAP PLEASE HELP

Mekhanik [1.2K]

Answer:

4a ) Difference ⇒ $ 63.24,

4b ) 4 children

Step-by-step explanation:

4a ) If the number of children is represented by the value of x, let us substitute a family of 2 children as value of x into this equation we are given;

y = 21.08 * ( 2 ) + 85.15 ⇒ Multiply 21.08 by 2,

y = 42.16 + 85.15 ⇒ Combine like terms,

y = 127.31

If y ⇒ amount spent on grocery's, let us solve for the amount spent on 5 children, and subtract from this amount;

y = 21.08 * ( 5 ) + 85.15 ⇒ Multiply 21.08 by 5,

y = 105.4 + 85.15 ⇒ Combine like terms,

y = 190.55

Difference; 190.55 - 127.31 = 63.24,

Solution; Difference ⇒ $ 63.24

4b ) If the amount is $ 169.47, let us plug it into our given equation provided amount spent on groceries ⇒ y;

169.47 = 21.08x + 85.15 ⇒ Subtract 85.15 from either side of equation,

21.08x = 84.32 ⇒ Divide either side 21.08,

x = 4 children

Solution; 4 children

5 0

3 years ago

Suppose the professor decides to grade on a curve. If the professor wants 2.5% of the students to get an A, what is the minimum

Fed [463]

It depends on how well the rest of the class does. A safe bet is usually a 93 for an A.

8 0

3 years ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

If ΔGET≅ΔMAP, then what corresponding parts are congruent? segment TG and segment AM ∠T and ∠P segment MP and segment ET ∠E and

otez555 [7]

Answer:

2nd Option is correct that is ∠T and ∠P.

Step-by-step explanation:

We are given that ΔGET ≅ ΔMAP

We need to find Congruent part from the given options.

Since, we are given the figure of the congruent triangles with marking not any instruction with which vertex is congruent to which vertex.

So, The Given Name of the Congruent triangle.

We deduce that

G ↔ M

E ↔ A

T ↔ P

Using this we get following congruent parts,

GE ≅ MA , GT ≅ MP and ET ≅ AP

∠G ≅ ∠M , ∠E ≅ ∠A and ∠T ≅ ∠P.

Therefore, 2nd Option is correct that is ∠T and ∠P.

3 0

4 years ago

Read 2 more answers

Please help!posted picture of question

ale4655 [162]

We have the following arithmetic series:
4, 13, 22, 31, 40
The common difference is given by:
13-4 = 9
22-13 = 9
31-22 = 9
40-31 = 9
Since it is an arithmetic series, the difference is constant.
Answer:
The common difference is:
9
option 4

7 0

3 years ago