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MA_775_DIABLO [31]
3 years ago
12

Can someone explain why this is correct please!!! help I have a 1hr !!

Mathematics
1 answer:
Anastaziya [24]3 years ago
5 0

Step-by-step explanation:

Domain = {5,x}

Range = {-2, y}

For being a function, one domain cannot have more than one range.

If x=5, then y will be the range for x=5. But 5 already has a range -2 in (5,-2). So, x can be any real number except 5 and y can be any real number

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Autos de F 1. En un circuito de Australia, Hamilton hizo el récord de vuelta. Si lo normal a 240km/h para completar el circuito
olga2289 [7]

Answer:

Tenía que hacerlo en menos de 2 minutos a más de 240 km/h

Step-by-step explanation:

La velocidad normal dada para completar el circuito de 6.000 metros = 240 km/h

El tiempo normal que se tarda en completar el circuito de 6000 metros = 2 minutos

Dado que Hamilton estableció el récord de vuelta, el tiempo que tuvo que hacer para recorrer el récord de vuelta es de 6000 metros en menos de 2 minutos

La velocidad media con la que lo hizo es de más de 240 km/h.

6 0
3 years ago
Evaluate the summation of negative 2 n minus 3, from n equals 2 to 10..
Alisiya [41]
\bf \sum\limits_{n=2}^{10}~-2n-3

so, let's first change the bounds from 1 to 9, so we'll be dropping the indices by 1, in order to do the variable "n".

however, let's use a variable hmmm say "k", where "k" is the value of "n" beginning at 1, thus k = n - 1.

however, if k = n - 1, then k + 1 = n.  So let's use those fellows then,

\bf \sum\limits_{n=2}^{10}~-2n-3\qquad 
\begin{cases}
k=n-1\\
k+1=n
\end{cases}\implies \sum\limits_{k=1}^{9}~-2\stackrel{n}{(k+1)}-3
\\\\\\
\sum\limits_{k=1}^{9}~-2k-2-3\implies \sum\limits_{k=1}^{9}~-2k-5\implies \sum\limits_{k=1}^{9}~-2k-\sum\limits_{k=1}^{9}~5
\\\\\\
-2\sum\limits_{k=1}^{9}~k-\sum\limits_{k=1}^{9}~5\implies -2\left( \cfrac{9(9+1)}{2} \right)\qquad -\qquad (9\cdot 5)
\\\\\\
-2(45)-45\implies -90-45\implies -135
5 0
3 years ago
Which expressions have products less than 3 3/5?<br> (Select all that apply)
Sergeeva-Olga [200]
1, 3 and 4.

1. 3,6>0,9
2. 3,6<4,725
3. 3,6>1,575
4. 3,6>0,54
3 0
3 years ago
The value of a jewel in 2015 was $17500. The jewel was purchased in 2008, and its value appreciated 2.5%
ArbitrLikvidat [17]

Answer:

$14722.14

Step-by-step explanation:

We are given that

In 2015

The value of jewel=$17500

Rate of appreciation, r=2.5%

We have to find the initial value of the jewel when it was first bought.

Time, n=7 years

Final value=Initial\;value (r/100+1)^n

Using the formula

17500=Initial\;value(2.5/100+1)^7

17500=Initial\;value(1.025)^7

Initial\;value=\frac{17500}{(1.025)^7}

Initial value=$14722.14

Hence, the the initial value of the jewel when it was first bought=$14722.14

5 0
3 years ago
Can you help me plz i will give you brainly its
hodyreva [135]
The answer is 3.5 + 1.5x = 12.5. So the answer would be C.
4 0
3 years ago
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