Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
Answer:
Answer is below
Step-by-step explanation:
Answer:
Step-by-step explanation:
(x+5)² = 36
x+ 5 = ±√36 = ±6
x = -5 ±6 = 1, -11
Answer:
26/3
Step-by-step explanation:
First, you need to turn the fractions from mixed form to improper fractions.
3 1/4 x 2 2/3
13/4 x 8/3
13/4 x 8/3
= 26/3
