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masha68 [24]
3 years ago
10

Sets - Venn Diagram Needing help with the second part of this question

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0

Answer:

{2,4,5,6,7,8,9,10,11,12,13,14,15,16,19,20}

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Rectangle FGHJ is transformed according to the rule T(–3, –2)ry = x. What is the y-coordinate of J”?
irga5000 [103]
We have that
 the point J (10,-6)
the rule is-----------(x,y)-------------------> (x-3, y-2)
therefore
J (10,-6)----------------- > (10-3,-6-2)--------> (7,-8)

the answer is 
<span>the y-coordinate of J” is -8</span>
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4 years ago
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Solve pls brainliest
otez555 [7]

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3 years ago
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Utiliza la formula De la distancia para calcular la medida De Los segmentos M(2,2) yN(5,-1)MN​
iren [92.7K]

Answer:

\huge{ \boxed{ \sf{ \sqrt{18}  \: units}}}

Step-by-step explanation:

\star{ \sf{ \:Sea  \: M (2, 2)  \: (x1, y 1) \:  y  \: N (5, -1) \:  sea  \: (x2, y2).}}

\star{ \sf{ \: Usando \:  la \:  fórmula  \: de  \: la  \: distancia}} :

\boxed{ \sf{distancia = \:   \sqrt{ {(x2 - x1)}^{2} +  {(y2 - y1)}^{2}  }    }}

\mapsto{ \sf{distancia \:  =  \:  \sqrt{ {(5 - 2)}^{2}  +  {( - 1 - 2)}^{2} } }}

\mapsto{ \sf{distancia =  \sqrt{ {(3)}^{2} +  {( - 3)}^{2}  } }}

\mapsto{ \sf{distancia  \:  =  \sqrt{9 + 9}}}

\mapsto{ \sf{distancia =   \sqrt{18}  \: units}}

\sf{¡Espero  \: haber  \: ayudado!}

\sf{¡Atentamente!}

~\text{TheAnimeGirl}

3 0
3 years ago
1. What form is the function below written in? *
Crank

Answer:

intercept form

(sometimes called factored form)

Step-by-step explanation:

8 0
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PLEASE HELP IM BEGGING YOU. PLEASE DONT ANSWER IF YOU DONT KNOW.
kirill [66]

Answer:

5.460

Step-by-step explanation:

6 0
3 years ago
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