Answer: 55.1°F
Step-by-step explanation:
We are informed that there is a 1.6°F drop in temperature for every thousand feet that an airplane climbs into the sky, if the plane reaches an altitude of 2,000ft, the drop in temperature will be:
= 1.6° × 2
= 3.2°F
If the temperature on the ground is 58.3°F, then the temperature when the plane reaches an altitude of 2,000 ft will be:
= 58.3°F - 3.2°F
= 55.1°F
Answer:
Altitude of the jet is 10.40km
Step-by-step explanation:
The angle of elevation = 8°
Horizontal distance (adjacent to the angle) = 74km
Altitude of the plane (opposite) = ?
Kindly check attached document for better illustration.
To solve this question, we have to use tangent rule since we have adjacent and angle, but no opposite.
Tanθ = opposite / adjacent
θ = 8°
Adjacent = 74km
Opposite = ?
Tan 8 = x / 74
Opposite = 74 * tan8
Opposite = 10.40
The altitude of the jet is 10.40km
I believe the answer would be 6.
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Answer:
V≈12308.8
Step-by-step explanation:
V=πr2h
V=(3.14)(14)2(20)
R=14cm
H=20cm
π=3.14