Item 5

The length of the base of an isosceles triangle is x. The length of a leg is 4x-2. The perimeter of the triangle is 122 . Find x

kirza4 [7]

There you go that’s the answer

4 0

3 years ago

PLZ hep thank you! :) Estimate a 15% tip on a dinner bill of $63.45 by first rounding the bill amount to the nearest ten dollars

gizmo_the_mogwai [7]

Answer:

Calculate tip at a restaurant. Enter cost and tip percent to get a tip amount and total dinner amount. Also split the ... Answer is in dollars and cents or rounded to dollars. ... You can find 10% of your bill by moving the decimal one place to the left. ... To find 15%, halfway in between, we know 15% is 10% plus 1/2 of 10% (5%).

Step-by-step explanation:

3 0

3 years ago

If y varies directly as x, and y is 48 when x is 6, give an expression can be used to find the value of y when x is 2?

Contact [7]

As both x and y varies directly and also when y is 48 then x is 6 so the expression must be
y = 8x

so when x = 2 then according to relation ...

y = 8x
y = 8*2
y = 16

hope it helped

7 0

3 years ago

The equation of the function h is h... PLEASE HELP MATH

Oduvanchick [21]

Answer:

Part A) $h(4) -m(16)=-4$

Part B) The distance between the y-intercepts is equal to 4 units

Part C) The value of h(x) will always be greater than the value of m(x) for any value of x

Step-by-step explanation:

Part A) What is the value of h(4) -m(16)

we have

$h(x)=\frac{1}{2}(x-2)^2$

For x=4

$h(4)=\frac{1}{2}(4-2)^2=2$

Find the equation of the line m(x)

Find the slope

take the points

(8,2) and (12,4)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute

$m=\frac{4-2}{12-8}$

$m=\frac{2}{4}$

$m=\frac{1}{2}$

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$m=\frac{1}{2}$

$point\ (8,2)$

substitute

$2=\frac{1}{2}(8)+b$

solve for b

$b=-2$

$y=\frac{1}{2}x-2$

therefore

$m(x)=\frac{1}{2}x-2$

Find m(16)

$m(16)=\frac{1}{2}(16)-2=6$

so

$h(4) -m(16)=2-6=-4$

Part B) we know that

The y-intercept is the value of y when the value of x is equal to zero

Find the y-intercept of h(x)

For x=0

$h(0)=\frac{1}{2}(0-2)^2=2$

Find the y-intercept of m(x)

For x=0

$m(0)=\frac{1}{2}(0)-2=-2$

therefore

The distance between the y-intercepts is equal to 2-(-2)=4 units

Part C)

Graph both equations

$h(x)=\frac{1}{2}(x-2)^2$

$m(x)=\frac{1}{2}x-2$

using a graphing tool

see the attached figure

The value of h(x) will always be greater than the value of m(x) for any value of x

4 0

3 years ago

Graph y < x2 + 4x. Click on the graph until the correct graph appears.

jonny [76]

Answer: The correct answer is:

_________________________

The given "graph" in the bottom right, lowest corner

Step-by-step explanation:

_________________________

Note: When there is only one (1) equation give for a graph;

and/or: only one (1) "inequality given";

we look for the symbol.

If the symbol is "not" an "equals" symbol (i.e. not an: = symbol) ;

we check for the type of "inequality" symbol.

If there is a: "less than" (<) ; or a "greater than" (>) symbol; the graph of the "inequality" will have "dashed lines" (since there will be a "boundary").

If there is an "inequality" that is a: "less than or equal to" (≤) ;

or a: "greater than or equal to" (≥) ;

→ then there will be not be a dashed line when graphed;

but rather—a "solid line" ; since "less than or equal to" ;

or "greater than or equal to" —is similar to:

"up to AND including"; or: "lesser/fewer than AND including".).

_________________________

Note: We are given the "inequality" :

→ " y < x² + 4x " .

_________________________________

Note that we have a "less than" symbol (< ) ; so the graph will have a:

"solid line" [and not a "dotted line".].

_________________________________

Note that all of the graphs among our 4 answer choices have "dotted lines".

Not that all values (all x and y coordinated) within the "shaded portion" of the corresponding graph are considered part of the graph.

As such, given any point within the shaded part, the x and y coordinates must match the inequality (i.e. the given inequality must be true when one puts in the "x-coordinate" and "y-coordinate" into the "given inequality" :

→ " y < x² + 4x " .

_________________________

Likewise, we can take any point within the "white, unshaded" portion of any of the graph, and take the "x-coordinate" and "y-coordinate" of that point, and the inequality: → " y < x² + 4x " ; will not hold true when the "x-coordinate" and "y-coordinate" values of that point— are substituted into the "inequality".

_________________________

{Note: Answer is continued on images attached.}.

Wishing you the best!

6 0

3 years ago