The cars will be 330 miles apart after three hours (1.00 pm) from 10.00 am (starting time).
<u>Step-by-step explanation:</u>
Data given for first car,
Rate (speed of car 1) = 60 miles/hour
Distance can be calculated by considering ‘X’ for time as,
![\text {rate}=\frac{\text {distance}}{\text {time}}](https://tex.z-dn.net/?f=%5Ctext%20%7Brate%7D%3D%5Cfrac%7B%5Ctext%20%7Bdistance%7D%7D%7B%5Ctext%20%7Btime%7D%7D)
![distance of first car = rate \times time =60 \times X miles](https://tex.z-dn.net/?f=distance%20of%20first%20car%20%3D%20rate%20%5Ctimes%20time%20%3D60%20%5Ctimes%20X%20miles)
Similarly, data given for first car
Rate (speed of car 2) = 50 miles/hour
![distance of second car = rate \times time =50 \times X miles](https://tex.z-dn.net/?f=distance%20of%20second%20car%20%3D%20rate%20%5Ctimes%20time%20%3D50%20%5Ctimes%20X%20miles)
Need to calculate at what time both the cars are 330 miles apart, so the equation would be,
Distance of first car + distance of second car = 330 miles
60 X + 50 X = 330
110 X = 330
![X=\frac{330}{110}=3 \text { hours }](https://tex.z-dn.net/?f=X%3D%5Cfrac%7B330%7D%7B110%7D%3D3%20%5Ctext%20%7B%20hours%20%7D)
Already given that both the cars leave at 10.00 am, so the time would be 10 am + 3 hours = 1.00 pm.
Hence, it takes three hours for the cars to get 330 miles apart.