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tia_tia [17]
3 years ago
13

7/3+3(2/3−1/3)^2 Simplify please!!!!

Mathematics
1 answer:
GarryVolchara [31]3 years ago
4 0

Answer:

Yeah no worry there is

exact form 8/3

decimal 2.6

mixed number 2 2/3

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What is 3/5 of 7 need help asap as i am not very good at maths thanks :-)
MAVERICK [17]
3/5 of 7

= (3/5) * 7

= 3 * 7/5

= 21/5

= 4.2


I hope this helps. =)
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3 years ago
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Given that sinθ=3/5
GrogVix [38]

Answer:

cos θ = 4/5.

tan θ = 3/4.

Step-by-step explanation:

Given sin θ = 3/5, we can find the value for the other side of the right triangle.

Using the Pythagorean formula, we can derive the value of this other leg.

5² = 3² + x²

x = 4.

Since sin θ is O/H, the Hypoteneus is 5 and the Opposite side is 3. The Adjacent side is 4, which will be used when finding cos θ and tan θ.

cos θ= A/H --> cos θ = 4/5.

tan θ= O/A --> tan θ = 3/4.

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4 years ago
5. Calculate 110/11.<br> O A. 9<br> O B. 11<br> O C. 10<br> OD. 12
Naddika [18.5K]

Answer:

A

Step-by-step explanation:

Good afternoon hope it is helpful

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3 years ago
Maths functions <br> please help!
Vlad [161]

Answer:

\textsf{1)} \quad f(x)=-x+3

2)   A = (3, 0)  and C = (-3, 0)

\textsf{3)} \quad g(x)=x^2-9

4)  AC = 6 units and OB = 9 units

Step-by-step explanation:

Given functions:

\begin{cases}f(x)=mx+c\\g(x)=ax^2+b \end{cases}

<h3><u>Part (1)</u></h3>

Given points:

  • H = (-1, 4)
  • T = (4, -1)

As points H and T lie on f(x), substitute the two points into the function to create two equations:

\textsf{Equation 1}: \quad f(-1)=m(-1)+c=4 \implies -m+c=4

\textsf{Equation 2}: \quad f(4)=m(4)+c=-1 \implies 4m+c=-1

Subtract the first equation from the second to eliminate c:

\begin{array}{r l} 4m+c & = -1\\- \quad -m+c & = \phantom{))}4\\\cline{1-2}5m \phantom{))))}}& = -5}\end{aligned}

Therefore m = -1.

Substitute the found value of m and one of the points into the function and solve for c:

\implies f(4)=-1(4)+c=-1

\implies c=-1-(-4)=3

Therefore the equation for function f(x) is:

f(x)=-x+3

<h3><u>Part (2)</u></h3>

Function f(x) crosses the x-axis at point A.  Therefore, f(x) = 0 at point A.

To find the x-value of point A, set f(x) to zero and solve for x:

\implies f(x)=0

\implies -x+3=0

\implies x=3

Therefore, A = (3, 0).

As g(x) = ax² + b, its axis of symmetry is x = 0.

A parabola's axis of symmetry is the midpoint of its x-intercepts.

Therefore, if A = (3, 0) then C = (-3, 0).

<h3><u>Part (3)</u></h3>

Points on function g(x):

  • A = (3, 0)
  • G = (1, -8)

Substitute the points into the given function g(x) to create two equations:

\textsf{Equation 1}: \quad g(3)=a(3)^2+b=0 \implies 9a+b=0

\textsf{Equation 2}: \quad g(1)=a(1)^2+b=-8 \implies a+b=-8

Subtract the second equation from the first to eliminate b:

\begin{array}{r l} 9a+b & =  \phantom{))}0\\- \quad a+b & =-8\\\cline{1-2}8a \phantom{))))}}& =  \phantom{))}8}\end{aligned}

Therefore a = 1.

Substitute the found value of a and one of the points into the function and solve for b:

\implies g(3)=1(3^2)+b=0

\implies 9+b=0\implies b=-9

Therefore the equation for function g(x) is:

g(x)=x^2-9

<h3><u>Part 4</u></h3>

The length AC is the difference between the x-values of points A and C.

\implies x_A-x_C=3-(-3)=6

Point B is the y-intercept of g(x), so when x = 0:

\implies g(0)=(0)^2-9=-9

Therefore, B = (0, -9).

The length OB is the difference between the y-values of the origin and point B.

\implies y_O-y_B=0-(-9)=9

Therefore, AC = 6 units and OB = 9 units

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Express this number in scientific notation.<br> 13,040,000
sp2606 [1]
Move the decimal behind the first number(1) then count how many spaces you moved and that is your power. 1.304×10^7
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