Question

Please help on this question :) tyyy

Answer 1

Answer:

$\mathrm{x_1=99/49-\sqrt38221/49;x_2=99/49+\sqrt38221/49}$

Step-by-step explanation:

Analyze the function:

f(x)=$-4.9x^{2}$+19.8x+58

To find the x-intercept, set y=0:

$-4.9x^{2}$ + $19.8_{x}$ + 58 = 0

Convert decimal to fraction:

$-\frac{49}{10}x^{2}$ + $\frac{99}{5}$x+58=0

Reduce the fraction:

$-\frac{49}{10}$ $x^{2}$ + $\frac{99}{5}$ x + 58 = 0

Multiply both sides of the equation by the common denominator:

$-\frac{49x10}{10}$×$x^{2}$+$\frac{99x10}{5} x$ × + 58 × 10 = 0 × 10

Reduce the fractions:

$-49x^{2}+198x$ + 58 × 10 = 0 × 10

Calculate the product or quotient:

-49$x^{2}+198x+580=0$

Make the leading coefficient positive:

49$x^{2} -198x-580=0$

Identify the coefficients:

a = 49, b = -198, c = -580

Substitute into x = $\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-\left(-198\right)+\sqrt{{(-198)}^2-4\times49\times(-580)}}{2\times49}$

or

$x=\frac{-(-198)-\sqrt{{(-198)}^2-4\times49\times(-580)}}{2\times49}$

Combine the results:

$x=\frac{99+\sqrt{38221}}{49}\ or\ x=\frac{99\ -\ \sqrt{38221}}{49}$