Can Somone help me please :))

A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as ed

Y_Kistochka [10]

Answer:

X=3252

Step-by-step explanation:

Your formula is $49645+$12.25x=$15499+$22.75x

X represents the number of books sold.

$49645+($12.25*3525)=$39,837

$15499+($22.75*3252)=$39,837

5 0

3 years ago

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On a recent trip, Juan started at an elevation of 1200 feet above sea level. He descended into a valley 20.4 feet below sea leve

liraira [26]

A would be the correct answer because he is up in elevation so that makes the 1200 positive and he goes down 20.4 which is negative and is goes that far down!!

hope this helps

3 0

3 years ago

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How can you use formulas you already know to find the area and perimeter of a composite figure? The six lane track shown in the

evablogger [386]

The area of the composite figure = 10,874.1 sq. m.

The perimeter of the composite figure = 406.9 m

<h3>What is the Area and Perimeter of a Rectangle and Circle?</h3>

Perimeter of a rectangle = 2(length + width)

Area of a rectangle = length × width

Perimeter of a circle = 2πr

Area of a circle = πr²

<h3>What is Area of the composite figure?</h3>

The figure is made up of two semicircles (1 full circle) and a rectangle.

Area of the composite figure = area of circle + area of rectangle

= πr² + length × width

r = 36.5 + 1.2 = 37.7 m

length = 85.0 m

width = 2(36.5) + 2(1.2) = 75.4 m

Substitute

Area of the composite figure = π(37.7)² + 85.0 × 75.4 = 10,874.1 sq. m.

<h3>What is Perimeter of the Composite Figure?</h3>

Perimeter of the composite figure = perimeter of circle + 2(length of the rectangle)

= 2πr + 2(L)

Plug in the values

= 2π(37.7) + 2(85.0)

Perimeter of the composite figure = 406.9 m

Learn more about composite figures on:

brainly.com/question/391747

6 0

2 years ago

A stock has a P/E ratio of 3.25 and a earnings per share of $9.25. What is the price per share of the stock?

astra-53 [7]

Answer:

$6.00

Step-by-step explanation:

7 0

3 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago