The solution (x,y) needs to work in both equations. With multiple choice you can do guess and test method. Otherwise you need to combine the two equations into one by substitution or elimination methods.
21. substitution works well here since one equation is y= x+3. you can easily substitute the (x+3) for y in the other equation. 2x + (x+3) = -6 3x + 3 = -6 3x = -9 x = -3 use this in either equation to find y. y = (-3)+3 solution: (-3,0)
22. these both equal y so they equal each other. 4x - 1 = 3x +6 4x - 3x = 6 + 1 x = 7 use this in either equation to find y y = 4(7) - 1 y = 28 - 1 y = 27 solution: (7,27)
23. one equation is y = 2x - 3. So substitute (2x -3) for y in the other equation. 4x = 2(2x - 3) + 6 4x = 4x - 6 + 6 4x = 4x x = x any solution will work, infinitely many.
24. infinitely many solutions means the two equations are the same equation. Like the previous one they didn't look the same but if you put them both in terms of y... y= 2x-3 4x = 2y + 6 4x - 6 = 2y (4x - 6)/2 = y 2x - 3 = y same equation.
from the image, I can't see all options but A & C do not look like the same equations. It's got to be either B or D.
C because it would be -x so x would be on the other side of 0 on the number line. Then you would add 3 so you would go 3 spaces to the right giving you point C
