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Andreyy89
3 years ago
9

Solve the inequality below, then determine which number line shows the solution graphed correctly.

Mathematics
2 answers:
irga5000 [103]3 years ago
7 0

Answer:

Line B

Step-by-step explanation:

2x-6<2

+6 +6

2x<8

/ /

2 2

x<4

It's Number Line B. All symbols are supposed to be less than or equal to, just don't have that symbol on my keyboard.

beks73 [17]3 years ago
4 0

Answer:

B

Step-by-step explanation:

2x-6 is \leq 2 is what you start with and first, you would have to move the 6 to the other side to isolate the 2x. To do that, you do the opposite operation of the 6 which is addition. Add 6 to both sides to the eqaution would end up being 2x\leq8. Now to isolate the x, we also have to do the opposite operation so divide the 2x and the 8 by 2. The eqaution would look like this x \leq4. Number line B would show this ineqaulity as the arrow is going left to show that x is less than 4 but the dot is also shaded in which means that 4 can also be the answer as well. Hope this helps:)

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Which is a y-intercept of the continuous function in the table ? A.(0,-6) B.(-2,0) C.(-6,0) D.(0,-2)
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A. (0, -6)

Step-by-step explanation:

when x is 0, there has to be a y-int. As shown in the table, it is -6. Therefore the answer is A

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3 years ago
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Use technology or a z-score table to answer the question.
Alik [6]

Answer:

The second choice: Approximately 65.2\% of the pretzel bags here will contain between 225 and 245 pretzels.

Step-by-step explanation:

This explanation uses a z-score table where each z entry has two decimal places.

Let \mu represent the mean of a normal distribution of variable X. Let \sigma be the standard deviation of the distribution. The z-score for the observation x would be:

\displaystyle z = \frac{x - \mu}{\sigma}.

In this question,

  • \mu = 240.
  • \sigma = 9.3.

Calculate the z-score for x_1 = 225 and x_2 = 245. Keep in mind that each entry in the z-score table here has two decimal places. Hence, round the results below so that each contains at least two decimal places.

\begin{aligned} z_1 &= \frac{x_1 - \mu}{\sigma} \\ &= \frac{225 - 240}{9.3} \approx -1.61\end{aligned}.

\begin{aligned} z_2 &= \frac{x_2 - \mu}{\sigma} \\ &= \frac{245 - 240}{9.3} \approx 0.54\end{aligned}.

The question is asking for the probability P(225 \le X \le 245) (where X is between two values.) In this case, that's the same as P(-1.61 \le Z \le 0.54).

Keep in mind that the probabilities on many z-table correspond to probability of P(Z \le z) (where Z is no greater than one value.) Therefore, apply the identity P(z_1 \le Z \le z_2) = P(Z \le z_2) - P(Z \le z_1) to rewrite P(-1.61 \le Z \le 0.54) as the difference between two probabilities:

P(-1.61 \le Z \le 0.54) = P(Z \le 0.54) - P(Z \le -1.61).

Look up the z-table for P(Z \le 0.54) and P(Z \le -1.61):

  • P(Z \le 0.54)\approx 0.70540.
  • P(Z \le -1.61) \approx 0.05370.

\begin{aligned}& P(225 \le X \le 245) \\ &= P\left(\frac{225 - 240}{9.3} \le Z \le \frac{245 - 240}{9.3}\right)\\&\approx P(-1.61 \le Z \le 0.54) \\ &= P(Z \le 0.54) - P(Z \le -1.61)\\ &\approx 0.70540 - 0.05370 \\& \approx 0.65.2 \\ &= 65.2\% \end{aligned}.

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hope it helps

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