1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
murzikaleks [220]
4 years ago
9

The Central Limit Theorem tells us that for population distribution(s), if we repeatedly take new random samples from this distr

ibution and calculate the average each time, then: a. If you take a really large sample size you would expect the sample average to be b. If your sample size is small, the sample averages will be spread out. c. If your sample size is small, the distribution of the sample averages will look more like distribution. d. If your sample size is very large, the distribution of the sample averages will look more like distribution.
Mathematics
1 answer:
sertanlavr [38]4 years ago
7 0

Answer:

d. If your sample size is very large, the distribution of the sample averages will look more like distribution.

Step-by-step explanation:

The central limit Theorem states that for population distribution if you repeatedly take samples from the distribution, then the normal thing for it to happen would be that the distribution means of the samples will be normally distributed, this is what it states, the option that comes closer to that statement would be  d. If your sample size is very large, the distribution of the sample averages will look more like distribution, because they large sample will create for a normally distributed means distribution.

You might be interested in
A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds
meriva
The answer is 4 m/s.

In the first 5 seconds, a body travelled 10 meters. In the first 10 seconds of the travel, the body travelled a total of 30 meters, which means that in the last 5 seconds, it travelled 20 meters (30m + 10m).
The relation of speed (v), distance (d), and time (t) can be expressed as:
v = d/t

We need to calculate the speed of the second 5 seconds of the travel:
d = 20 m (total 30 meters - first 10 meters)
t = 5 s (time from t = 5 seconds to t = 10 seconds)

Thus:
v = 20m / 5s = 4 m/s
5 0
3 years ago
Read 2 more answers
Please help! due in next 10min!?!
Paladinen [302]

Answer:

21.99

Step-by-step explanation:

This is simple just times 3.14 and 7 to get 21.99

7 0
3 years ago
Read 2 more answers
What is 2x =6.5<br><br> And how
Leona [35]

Answer:

Step-by-step explanation:

2x =6.5

To find the value of x, divide both sides by 2 so you will have 1x.

x = 3.25

8 0
2 years ago
Read 2 more answers
Suppose that a box contains r red balls and w white balls. Suppose also that balls are drawn from the box one at a time, at rand
dybincka [34]

Answer: Part a) P(a)=\frac{1}{\binom{r+w}{r}}

part b)P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}

Step-by-step explanation:

The probability is calculated as follows:

We have proability of any event E = P(E)=\frac{Favourablecases}{TotalCases}

For part a)

Probability that a red ball is drawn in first attempt = P(E_{1})=\frac{r}{r+w}

Probability that a red ball is drawn in second attempt=P(E_{2})=\frac{r-1}{r+w-1}

Probability that a red ball is drawn in third attempt = P(E_{3})=\frac{r-2}{r+w-1}

Generalising this result

Probability that a red ball is drawn in [tex}i^{th}[/tex] attempt = P(E_{i})=\frac{r-i}{r+w-i}

Thus the probability that events E_{1},E_{2}....E_{i} occur in succession is

P(E)=P(E_{1})\times P(E_{2})\times P(E_{3})\times ...

Thus P(E)=\frac{r}{r+w}\times \frac{r-1}{r+w-1}\times \frac{r-2}{r+w-2}\times ...\times \frac{1}{w}\\\\P(E)=\frac{r!}{(r+w)!}\times (w-1)!

Thus our probability becomes

P(E)=\frac{1}{\binom{r+w}{r}}

Part b)

The event " r red balls are drawn before 2 whites are drawn" can happen in 2 ways

1) 'r' red balls are drawn before 2 white balls are drawn with probability same as calculated for part a.

2) exactly 1 white ball is drawn in between 'r' draws then a red ball again at (r+1)^{th} draw

We have to calculate probability of part 2 as we have already calculated probability of part 1.

For part 2 we have to figure out how many ways are there to draw a white ball among (r) red balls which is obtained by permutations of 1 white ball among (r) red balls which equals \binom{r}{r-1}

Thus the probability becomes P(E_i)=\frac{\binom{r}{r-1}}{\binom{r+w}{r}}=\frac{r}{\binom{r+w}{r}}

Thus required probability of case b becomes P(E)+ P(E_{i})

= P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}\\\\

7 0
4 years ago
Jean and Clint stack boxes at a warehouse. Jean stacks 50 boxes per hour. Clint stacks 60 boxes per hour. Which of the following
Valentin [98]
Represent the total number of boxes that both jean and clint stack in h hours,

total number of boxes=(50xh)+(60xh)
you want the total number of boxes for both of them together. so the amount they can stack times h or the hours. so if h=5 you would do 50x5 plus+ 60x5 which would give you 250 and 300. add the two you get 550 boxes for 5 hours total.
5 0
3 years ago
Other questions:
  • Why is a larger down payment beneficial to a home investor?
    12·2 answers
  • Follow these steps using the algebra tiles to solve the equation −5x + (−2) = −2x + 4. 1. Add 5 positive x-tiles to both sides a
    14·2 answers
  • 98 POINTS ONE GEOMETRY QUESTION PLEASE ANSWER!!!!!!!!!!!!!!!!!!!!!!!!
    8·2 answers
  • A circular pond has a radius of 3 feet. What is the approximate distance around the edge of the pond?
    15·2 answers
  • Someone pls help i don’t understand this
    11·1 answer
  • How to reduce 22/100 to its lowest term​
    7·2 answers
  • Distribute -(6 - 4p) TWELVE POINTS FOR YOUR ANSWER!!
    10·2 answers
  • Football fields are 360 ft in length and 160 ft in width. Find the area
    11·2 answers
  • ANSWER QUICK PLEASE!!
    13·2 answers
  • Please simplify the answer
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!