we can divide the composite shape into on quadrilateral and triangle as shown in the diagram. since the line that joins the two shape is parallel to the base AB, the angle DEC is 85°.The angle CEA is 180°- angle DEC = 180-85=95. Angle BCE is sum of angle CEA, ABC and EAB subtracted from360°= 360°-(95+95+85)=85°. Angle DCE is 120°- ECB=35°. So, angle CDE = 180°-(35°+85°)= 60°. For reference see the diagram.
Answer:
<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>Step-by-step explanation:
First alloy contains 34% copper and the second alloy contains 48% alloy.
We wish to make 46 pounds of a third alloy containing 37% copper.
Let the weight of first alloy used be in pounds and the weight of second alloy used be
in pounds.
Total weight =
Total weight of copper =
Subtracting 34 times first equation from second equation,
∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.