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Stels [109]
3 years ago
8

Complete the following statement. 3(4 x 8) (3 x4) (_)​

Mathematics
1 answer:
shutvik [7]3 years ago
8 0

Answer:

8

Step-by-step explanation:

(8*4)3=96

3*4=12

12*8=96

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Proof: sin(x) + cos(x) = √2sin(x + π/4)
Oksi-84 [34.3K]
Hello : 
sin(x) + cos(x) = √2(1/√2 sin(x) +1/√2 cos(x))
but : 1/√2 = cos(π/4) =   sin(<span> π/4)
</span>sin(x) + cos(x) = √2( cos(π/4)sin(x) + sin( π/4) cos(x)) =√2<span>sin(x + π/4)
</span>because : cos(π/4)sin(x) + sin( π/4) cos(x)=sin(x + π/4) by identity :
sin(a+b) = sina cosb +cosa sinb
5 0
3 years ago
The punch bowl at Felicia's party is getting low, so she adds 12 cups of punch to
astraxan [27]

Answer:

101

Step-by-step explanation:

final cups present-(cups added+cups two guest served)

5 0
3 years ago
Pls give answer for 9c thanks
harina [27]

Answer:

probability for 3 on a dice (P3) in one dice =

\frac{1}{6}

probability for even no. of a dice (Pe) =

\frac{3}{6}  =  \frac{1}{2}

Therefore, the probability of finding 3 on one dice and even on another (P) = P3 + Pe

=  \frac{1}{6}  +  \frac{1}{2}  =  \frac{1 + 3}{6}  =  \frac{4}{6}  =  \frac{2}{3}

7 0
1 year ago
I dont understand this problem
Fiesta28 [93]

Answer:

D and F

Step-by-step explanation:

x^{2}+4x+4=12 can be rewritten as x^{2} +4x-8=0.

From there you can use the quadratic formula x=\frac{-b±\sqrt{b^{2}+4ac } }{2a} (ignore the A, I can‘t seem to remove it), where a=1, b=4, and c=-8.

x=\frac{-4±\sqrt{4^{2}-4(1)(-8)} }{2(1)}

Then you get x=\frac{-4±\sqrt{16+32}}{2}

Then you get x=\frac{-4±\sqrt{48} }{2}

So x=-2±\frac{4\sqrt{3} }{2}

Which means x=-2+2\sqrt{3} or -2-2\sqrt{3} which are choices D and F.

8 0
2 years ago
HELP ASAP BEING TIMED! If Triangle J K L is congruent to Triangle B C A, which statement must be true?
Vlada [557]

Answer:

Choice C

Step-by-step explanation:

This is like a matching question. Here's what I mean by this. We know Triangle BCA and Triange JKL are congruent. So, what we have to do is match the side lengths together.

So the first side of BCA matches with JKL, the second side of BCA matches with JKL, the third side of BCA matches with JKL.

So first side:

BC is congruent  to JK

So second side:

CA is congruent  to KL

So third side:

JL is congruent  to BA

The third side is one of our answer choices.

That answer choice is C.

3 0
2 years ago
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