All categories

3 years ago

The diagram shows the solid glass case for a clock. The case is a cuboid with a cylinder

Mathematics

1 answer:

Karolina [17]3 years ago

5 0

Answer:

241.5cm³

Step-by-step explanation:

Volume of the glass = Volume of the cuboid - Volume of the cylinder

Volume of the cuboid = Length * width * height

Volume of the cuboid = 8cm * 4cm * 10cm

Volume of the cuboid = 320cm³

Volume of the cylinder = πr²h

Radius r = 5/2 = 2.5cm

height = 4cm

Volume of the cylinder = 3.14(2.5)²*4

Volume of the cylinder = 78.5cm^3

Volume of the glass = 320 - 78.5

Volume of the glass = 241.5cm³

You might be interested in

Two factory plants are making TV panels. Yesterday, Plant A produced 7000 fewer panels than Plant B did. Four percent of the pan

amid [387]

Step-by-step explanation:

17000

Let the number of panels Plant B produced be x.

$7000(0.04)+0.02x=620 \\ \\ 0.02x=340 \\ \\ x=17000$

8 0

2 years ago

Write three (3) scenarios that describe three different real-world functions. Each scenario should use two of the variables from

NISA [10]

Here is one <span>Jake’s salary depends on the number of hours he works.
The independent variable is the number of hours and the dependent variable is salary.
Let x = the number of hours worked
Let y = Jake's salary
The set of ordered pairs {(1, 10), (2, 20), (3, 30), (4, 40), (5, 50)} can be used to represent
the function, assuming Jake earns $10 per hour. </span>

8 0

3 years ago

Which of these polynomials will make the following equation true<br><br>

Amanda [17]

Poop I think good luck but it’s b x2-
512

4 0

3 years ago

PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS

Reil [10]

Given

$x+1 = \sqrt{7x+15}$

We have to set the restraint

$x+1\geq 0 \iff x \geq -1$

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

$(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0$

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

$x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}$

So, we have to impose

$x-7\geq 0 \iff x \geq 7$

Squaring both sides, we have

$(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0$

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

7 0

3 years ago

A hot-air balloon rises vertically at a constant rate of 8 m/s. A second hot-air balloon moves past the first hot-air balloon at

Lunna [17]

The second hot-air balloon is moving 5 m/s

8 0

4 years ago